The questions for this problem would be:
1. What is the dimensions of the box that has the maximum volume?
2. What is the maximum volume of the box?
Volume of a rectangular box = length x width x height
From the problem statement,
length = 12 - 2x
width = 9 - 2x
height = x
where x is the height of the box or the side of the equal squares from each corner and turning up the sides
V = (12-2x) (9-2x) (x)
V = (12 - 2x) (9x - 2x^2)
V = 108x - 24x^2 -18x^2 + 4x^3
V = 4x^3 - 42x^2 + 108x
To maximize the volume, we differentiate the expression of the volume and equate it to zero.
V = 4x^3 - 42x^2 + 108x
dV/dx = 12x^2 - 84x + 108
12x^2 - 84x + 108 = 0x^2 - 7x + 9 = 0
Solving for x,
x1 = 5.30 ; Volume = -11.872 (cannot be negative)
x2 = 1.70 ; Volume = 81.872
So, the answers are as follows:
1. What is the dimensions of the box that has the maximum volume?
length = 12 - 2x = 8.60
width = 9 - 2x = 5.60
height = x = 1.70
2. What is the maximum volume of the box?
Volume = 81.872
Answer: 
Step-by-step explanation:
Given
Equation is 
Mila uses the first step as multiplication to make the coefficient of x, 1
Mila maybe have multiplied the whole equation by 2 i.e.
Answer:
B.
Step-by-step explanation:
I did 46.20 divided by 12 and I got my answer.
Answer:4
Step-by-step explanation:collect like terms
2x-3x+10=2x-2
-1x+10=2x-2
-3x=-12
divide both sides by -3
x=4
9514 1404 393
Answer:
46
Step-by-step explanation:
The length of base CD is twice the length of midsegment FG, so you can write the equation ...
CD = 2×FG
-3x +52 = 2(13 +5x)
52 = 26 +13x . . . . . . . . add 3x, simplify
26 = 13x . . . . . . . . . subtract 26
2 = x . . . . . . . . . . divide by 13
Then the measure of CD is ...
CD = -3x +52 = -3(2) +52 = -6 +52
CD = 46
