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cricket20 [7]
3 years ago
9

purchased a toyota 4Runner for $25,635. promised your daughter the suv will be hers when the car is worth $10,000. according to

the car dealer the suv will depreciate approximately $3,000 per year,if your daughter is currently 15 years old, how old will she be when the 4Runner will be hers.
Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer:

  about 20

Step-by-step explanation:

The vehicle must decline in value by $25,635 -10,000 = $15,635. At the rate of $3000 per year, it will take ...

  15,635/3,000 ≈ 5.21167

In 5.2 years, she will be about 20 years old.

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OLEGan [10]

The answer for this problem is 3

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John had $20. He earned $5, spent $10, earned $5 again, and then spent $3. After this series of earings and expenses, how much m
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He has 17 dollars left
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I need some assistance please
zzz [600]

Answer:

2x + y = 20 .     y=3x

2x + 3x = 20

5x = 20

x/5 = 20/5

x = 4

(4,0)

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3 years ago
For what value of x is the rational expression below undefined?
Blizzard [7]

Answer: The expression is undefined for x=4 and x=5.

The expression is undefined for any x that makes the denominator 0. This leads to solving a quadratic equation:

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4 years ago
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Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0
4 years ago
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