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natka813 [3]
3 years ago
8

A satellite moves through space at a rate of 17, 208 kilometers per hour. What is this number in word form?

Mathematics
1 answer:
KonstantinChe [14]3 years ago
6 0

Answer:

Seventeen thousand, two hundred and eight kilometers per hour.

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What the median number for 4, 8 10 5 9
ZanzabumX [31]
Actually, the median is not the same as the average.
The mean and the average are the same.
To find the median, put these numbers in order.
So 4, 5, 8, 9, 10. Now see which number is in the middle.
It is 8, so 8 is the median number.
4 0
3 years ago
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James thinks of two numbers. He says "The Highest Common Factor (HCF) of my two numbers is 3 The Lowest Common Multiple (LCM) of
xxTIMURxx [149]

Answer: (3,45) and (15,9)

Step-by-step explanation:

LCM x HCF = 45*3 = 135

so, the pairs which has HCF as 3 and LCM as 45 are (3,45) and (15,9)

5 0
3 years ago
Answer please with the work thank you. Who ever answers geta the brainlest answer!​
vodomira [7]

Answer:

6

Step-by-step explanation:

cassie is going up 3 and then down 5

8 + 3=11

11-5= 6

8 0
3 years ago
The sum of the two shorter sides of a triangle must be equal to the longest side to be classified as a triangle
kogti [31]

Answer:

False

Step-by-step explanation:

For example if you follow the pythagoras theorem a triangle has sides of 3,4 and 5

but when you add 3 and 4 they do not give you 5

so that is false

5 0
3 years ago
KoKo Chocolatiers sells their truffes in rectangular boxes. They are going to start ordering circular boxes, too. The rectangula
lidiya [134]

Answer:

r = 9.61 cm

Step-by-step explanation:

Volume of a rectangular box = length × width × height

= 21.5 cm × 13.5 cm × 6 cm

= 1,741.5 cm³

Volume of a rectangular box = 1,741.5 cm³

Since,

Volume of a rectangular box = Volume of a circular box

Then,

1,741.5 cm³ = Volume of a circular box

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1,741.5 cm³ = 3.14 * r² * 6 cm

1,741.5 = 18.84r²

r² = 1,741.5/18.84

r² = 92.436305732484

r = √92.436305732484

r = 9.6143801533163

Approximately,

r = 9.61 cm

3 0
3 years ago
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