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Shkiper50 [21]
2 years ago
15

Christina goes to market with $50. She buys one papaya for $20 and spends the rest of the money on bananas. Each banana costs $6

.
Write an inequality for the number of bananas she can purchase?
Mathematics
1 answer:
maria [59]2 years ago
7 0
x-\ number\ of\ bananas\\\\
20+6x\leq50\ \ \ \ | subtract\ 20\\\\
6x\leq30\ \ \ | divide\ by\ 6\\\\
x\leq5\\\\
x\in(-\infty,5)
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Please answer this without making mistakes
den301095 [7]

Answer:

1 pound = 16 ounces

2 pounds = 32 ounces

Given:

Cost for 2 pounds of bananas = $1.28

Price per ounce = 1.28/32    [∵2 pounds = 32 ounces]

=$0.04

Hence the cost of bananas per ounce is $0.04

Hope it helped!

5 0
2 years ago
14 points to help me out with Geometry
Ede4ka [16]
Since f and g are parallel to eachother, the sum of the angle 7x and 2x+36 would equal 180. To solve for x, you add 7x+2x+36, set it equal to 180, and then solve for x. 

x= 16
4 0
2 years ago
Read 2 more answers
An object is launched at 29.4 meters per
Yuri [45]

Answer:

34.3 meters

Step-by-step explanation:

The generic equation for a movement with constant acceleration is:

S = So + Vo*t + (a*t^2)/2

Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.

If we compare with our equation (where x is the time and f(x) is the final distance), we have that:

So = 34.3

Vo = 29.4

a = -9.8

So we have that the inicial position (So) of the object is 34.3 meters

8 0
3 years ago
Paige works at a department store and has a commission rate of 3 percent. Her sales for the quarter were $4,596. If she earns $5
ivanzaharov [21]

Here's what the equation would look like:

30(50) + 0.03(4596)

1500 + 137.88

Paige earned $1637.88.

8 0
2 years ago
If a gym class is divided into 4 equal teams, 2 students have to sit out; 5 teams, 1 student has to sit out; 6 teams, 4 students
Sidana [21]

Answer:

14 students

Step-by-step explanation:

Let x be the number of students, x

  • If a gym class is divided into 4 equal teams, 2 students have to sit out, so x\equiv 2(\rm mod \ 4);
  • If a gym class is divided into 5 equal teams, 1 student has to sit out, so x\equiv 1(\rm mod \ 5);
  • If a gym class is divided into 6 equal teams, 4 students have to sit out, so x\equiv 4(\rm mod \ 6).

From the first congruence,

x=2+4k,

substitute it into the second congruence:

2+4k\equiv 1(\rm mod\ 5)\\ \\4k\equiv -1(\rm mod\ 5)\\ \\4k\equiv -1+5(\rm mod \ 5)\\ \\4k\equiv 4(\rm mod \ 5)\\ \\k\equiv 1(\rm mod \ 5)\\ \\k=5l+1\\ \\x=4(5l+1)+2=20l+6

Substitute this into the third congruence:

20l+6\equiv 4(\rm mod\ 6)\\ \\20l\equiv -2(\rm \ mod 6)\\ \\20l\equiv -2+6\cdot 7(\rm mod\ 6)\\ \\20l\equiv 40(\rm mod \ 6)\\ \\l\equiv 2(\rm mod 6)\\ \\l=6m+2\\ \\x=20(6m+2)+6=120m+46

Since x then x=46\ (\text{when }m=0)

The next number divisible by 4, 5 and 6, greater than 46 and less than 70 is 60, so 14 students should be added.

4 0
3 years ago
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