0.55 written as a decimal or mixed number in simplest form

2 answers:

7 0

$\frac{.55}{1} \times \frac{10}{10} = \frac{5.5}{10} \times \frac{10}{10 } = \frac{55}{100} \\ or \\ \frac{.55}{1} \times \frac{100}{100} = \frac{55}{100} \\ simplified \\$
$\frac{55}{100} \div \frac{5}{5} = \frac{11}{20}$

torisob [31]4 years ago

5 0

I guess you meant "write as a fraction".

$0.55=\dfrac{55}{100}=\dfrac{11}{20}$

You might be interested in

Help me with this problem please right away

svlad2 [7]

Answer:

$6\frac{1}{2} = A$

Step-by-step explanation:

The first step is to use the Distance Formula to figure out the lengths of the two legs:

$\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D$

R(1, 1) and P(−1, −2) ↷

$\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP$

Q(2, −4) and P(−1, −2) ↷

$\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP$

* So, by my calculations, we have an isosceles right triangle, and according to the 45°-45°-90° triangle theorem, we automatically know that the hypotenuse, RQ, is $\sqrt{26}$ :

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

45°-45°-90° triangle theorem

x√2, x, x

↑ ↑ ↑

h legs

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles right triangle, it does not matter:

$[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A$