I don’t know what your asking
Answer:
<em>0 $20 bills and 10 $5 bills</em>
<em>1 $20 bills and 6 $5 bills</em>
<em>2 $20 bills and 2 $5 bills</em>
Step-by-step explanation:
<u>Equations</u>
Let's set:
x=number of $5 bills
y=number of $20 bills
The total amount Sara has is given by
5x+20y
And we know it's equal to $50, thus:
5x+20y=50
Dividing by 5
x+4y=10
We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.
Solving for x:
x=10-4y
Since both x and y are integers and cannot be negative:
10-4y≥0
Swapping sides:
4y≤10
Dividing by 4:
y≤2.5
Thus, y can only have the values {0,1,2}
For y=0
x=10-4*0=10
x=10
For y=1
x=10-4*1=6
x=6
For y=2
x=10-4*2=2
x=2
Thus, the possible combinations are:
0 $20 bills and 10 $5 bills
1 $20 bills and 6 $5 bills
2 $20 bills and 2 $5 bills
The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the
distance in feet.
The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the
distance in feet.
9m
It said the sides are 25m (x2) and 9m(x2). The width of a rectangle are shorter than the length so 9m.
