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Greeley [361]
3 years ago
7

Please I need help?!

Mathematics
1 answer:
Contact [7]3 years ago
4 0

Answer:

-2 = -6

-1 = -1.5

0 = 0

1 = -1.5

2 = -6


i answered you other question too. plz give me brainliest and thank


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A certain triangle has two 45° angles, what type of triangle is it?
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A right triangle? because it has angle measures or 45, 45, 90. 
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5(–9a–1)+7?<br> so<br> me<br> on<br> e <br> an<br> sw<br> er<br> pl<br> ea<br> se
il63 [147K]

Answer:

5(–9a–1)+7=0

5(-9a-1)=-7

-9a-1=-7/5

9a+1=7/5

9a=7/5 +1

a=(7+5)/(5×9)=35/45=7/9

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Someone help me please! Thank u so much!!
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5. a^2 + b^2 = c^2...where a and b are the legs and c is the hypotenuse
    7^2 + 10^2 = c^2
    49 + 100 =c^2
    149 = c^2....take square root of both sides, eliminating the ^2
     sq rt 149 = c
     12.21 = c.....so the approximate length of 3rd side is 12 m

6. x = number of books bought

7. m < 2 + m < 8 = 180

8. 1000 = 400 + 24x
     1000 - 400 = 24x
     600 = 24x
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Simplify √ 105 . A. 2√ 3 B. √ 105 C. 2√ 7 D. √ 42
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B. \sqrt{105}

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8 0
3 years ago
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HW 7.4/7.5 help mhhhh
Hatshy [7]

Answer:

1. LI=18

2. x=10

3. Yes (Y)

4. Yes (Y)

5. x=15

6. x=18

7. x=8

8. x=6

   y=6.5

Step-by-step explanation:

1. LI/JL=KH/JK

Replacing the given values:

LI/6=21/7

Dividing on the right side of the equation:

LI/6=3

Solving for LI: Multiplying both sides of the equation by 6:

6(LI/6)=6(3)

LI=18


2.TV/VS=RU/US

Replacing the given values:

x/17.5=8/14

Simplifying the fraction on the right side of the equation: Dividing numerator and denominator by 2:

x/17.5=(8/2) / (14/2)

x/17.5=4/7

Solving for x: Multiplying both sides of the equation by 17.5:

17.5(x/17.5)=17.5(4/7)=(17.5/1)(4/7)

Multiplying:

x=(17.5 x 4) / (1 x 7)

x=70/7

Dividing:

x=10


3. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB=15/12=(15/3) / (12/3)→AD/DB=5/4

AE/EC=10/8=(10/2) / (8/2)→AE/EC=5/4

Like AD/DB=5/4=AE/EC → BC is parallel to DE


4. BC is parallel to DE if AD/DB is equal to AE/EC:

AD/DB= 2DB / DB→AD/DB=2

AE/EC=30 / (AC-AE)=30 / (45-30)=30/15→AE/EC=2

Like AD/DB=2=AE/EC → BC is parallel to DE


5. If JH is a midsegment of triangle KLM:

x=(1/2)(30)

x=15


6. If JH is a midsegment of triangle KLM:

x=2(9)

x=18


7. If JH is a midsegment of triangle KLM: x=8


8. 2x+1=x+7

Solving for x. Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

2x+1-x=x+7-x

Subtracting:

x+1=7

Subtracting 1 both sides of the equation:

x+1-1=7-1

Subtracting:

x=6

2x+1=2(6)+1=12+1→2x+1=13

x+7=6+7→x+7=13


(3y-8)/(y+5)=(2x+1)/(x+7)

(3y-8)/(y+5)=13/13

(3y-8)/(y+5)=1

3y-8=y+5

Solving for y. Grouping the y's on the left side of the equation: Subtracting y both sides of the equation:

3y-8-y=y+5-y

Subtracting:

2y-8=5

Adding 8 both sides of the equation:

2y-8+8=5+8

Subtracting:

2y=13

Dividing both sides of the equation by 2:

2y/2=13/2

Dividing:

y=6.5



3 0
3 years ago
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