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slega [8]
3 years ago
10

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

nd the probability of x successes given the probability p of success on a single trial. Round to three decimal places. n = 30, x = 12, p = 0.20
Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

P(X = 12) = 0.0064.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 30, p = 0.2

We want P(X = 12). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{30,12}.(0.2)^{12}.(0.8)^{18} = 0.0064

P(X = 12) = 0.0064.

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Well this problem can be solved with Algebra

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