Solve for x. 2(x-4)=x + 4 X=__

sasho [114]

1. 3x² + 12x - 15 = 0
 x = -(12) +/- √((12)² - 4(3)(-15))
 2(3)
 x = -12 +/- √(144 + 180)
 6
 x = -12 +/- √(324)
 6
 x = -12 +/- 18 
 6
 x = -2 + 3
 x = -2 + 3 x = -2 - 3
 x = 1 x = -5
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2. 5x² + 11x + 2 = 0
 x = -(11) +/- √((11)² - 4(5)(2))
 2(5)
 x = -11 +/- √(121 - 40)
 10
 x = -11 +/- √(81)
 10
 x = -11 +/- 9
 10
 x = -1¹/₁₀ + ⁹/₁₀
 x = -1¹/₁₀ + ⁹/₁₀ x = -1¹/₁₀ - ⁹/₁₀
 x = ¹/₅ x = -2
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3. 2x² - 11x + 14 = 0
 x = -(-11) +/- √((-11)² - 4(2)(14))
 2(3)
 x = 11 +/- √(121 - 102)
 6
 x = 11 +/- √(9)
 6
 x = 11 +/- 3
 6
 x = 1⁵/₆ + ¹/₂
 x = 1⁵/₆ + ¹/₂ x = 1⁵/₆ - ¹/₂
 x = 2¹/₃ x = 1¹/₃
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4. 2x² - x - 15 = 0
 x = -(-1) +/- √((-1)² - 4(2)(-15))
 2(2)
 x = 1 +/- √(1 + 120)
 4
 x = 1 +/- √(121)
 4
 x = 1 +/- 11
 4
 x = ¹/₄ + 2³/₄
 x = ¹/₄ + 2³/₄ x = ¹/₄ - 2³/₄
 x = 3 x = 2¹/₂

4 0

3 years ago

Hey can you please help me posted picture of question

svet-max [94.6K]

If we observe the graph we can see that the curve crosses the x-axis at the following points: 1, 3, and 5
This means x = 1, x = 3 and x = 5 are the roots of the polynomial and x - 1, x - 3 and x - 5 are the factors of the polynomial.

We can express the polynomial as the product of its factors. So the polynomial will be (x-1)(x-3)(x-5)

The correct answer to this question is option A

4 0

3 years ago

Read 2 more answers

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

Equation Solving

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

3 years ago

A crepe recipe calls for 2 eggs, 1 cup of flour, and 1 cup of milk. How much flour would you need if you use 5 eggs?

nataly862011 [7]

Answer: 2.5 cups of flour is needed for 5 eggs.

Step-by-step explanation:

The crepe recipe calls for 2 eggs, 1 cup of flour, and 1 cup of milk. This means that the ratio of eggs to cup of flour to cup of milk required is 2:1:1

Therefore, if you use 5 eggs, the proportions would increase by 2.5. Multiplying by 2.5, it becomes

5 : 2.5 : 2.5

Therefore, you would need 2.5 cups of flour for 5 eggs.

6 0

3 years ago

Read 2 more answers

Determine if the two triangles are congruent.

goldenfox [79]

Answer:

Yes

Step-by-step explanation:

Since they have 3 identical sides, they are congruent by SSS congruence.

HTH :)

6 0

2 years ago

Solve for x. 2(x-4)=x + 4 X=___