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3 years ago

1. Write numbers from standard form to Scientific notation for the following: The diameter of human DNA is about 0.000000002

1 answer:

4 0

Okay, so in order to find scientific notation you're going to either move the decimal place to the left or right in order to make your answer a number between 1 and 9. In this case you're going to need to move it right, because you need to make it bigger in order to make it a number between 1 and 9. You'll have to move the decimal 9 places to the right, which will give you the number 2. Since you are making the number bigger, your exponent will be negative. That happens anytime you move the decimal place to the right. To the left, your exponent will be positive. Therefore the answer to 1 is:
2.00X10^-9

As for number two, you must first start by using the area formula of a triangle. That equation would be
A= 1/2bh or A=bh/2 (b=base and h=height)
By plugging that in you get an area of 83,200 miles. As mentioned before, when finding scientific notation, you want a number between 1 and 9. To do so, we have to make this number smaller by moving the decimal 4 places to the left (making the exponent positive) and resulting in an answer of:
8.32X10^4 miles

You might be interested in

Give a direct proof that the sum an even integer and an odd integer is odd.

mina [271]

Even integer: 2 x a, where a is a natural number without 0;
Odd integer : 2 x b + 1 , where b is a natural number;
So, 2 x a + 2 x b+ 1 = 2 x ( a + b ) + 1, which is an odd integer.

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3 years ago

The SI unit for pressure is pascal (Pa). One hectopascal would equal how many pascals?

IgorLugansk [536]

Answer:

100 pascals would be your answer

have a great day ! ⭐️

8 0

3 years ago

What is the product?

ZanzabumX [31]

Answer:

The product is:

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

Step-by-step explanation:

For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:

$\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]$

$1 \times 2 + 3 \times 3 + 1 \times -2 = 15$

So the value of the element in the position $a_{11}$ is 15

$1 \times -2 + 3 \times 5 + 1 \times 1 = 14$

So the value of the element in the position $a_{12}$ is 14

Then with these two values you can determinate the result matrix.

$\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]$

3 0

2 years ago

Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als

MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D : Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC = (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0

3 years ago

What is the area of the triangle below?

stira [4]

Answer:

7.5 square units

Step-by-step explanation:

Base of the triangle = 5 units

Height of the triangle = 3 units

Area of the triangle

$= \frac{1}{2} \times base \times height \\ \\ = \frac{1}{2} \times 5 \times 3 \\ \\ = \frac{1}{2} \times 15 \\ \\ = 7.5 \: {units}^{2}$

6 0

3 years ago

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