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aliya0001 [1]
2 years ago
11

Can someone please help me ive been stuck in these questions for ages

Mathematics
1 answer:
earnstyle [38]2 years ago
8 0

Answer:

x = 2 (For First question)

Step-by-step explanation:

8^ 1/6 * 2^x = 32^1/2

8^1/6 * 2^x 8^1/6 = 32^1/2/8^1/6

2^x = 32^1/2 / 8^1/6

2^x = 4

2^x = 2^2

x =2

Question 2:

Answer: 50

Step-by-step explanation:

8^1/3/5^-2

= 2/5^-2

= 2/1/5^2

= 2*  5^2/1

= 2 * 5^2

= 2 * 25

= 50

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When they arrived in Philadelphia, Tyler’s family took a taxi to a museum. The taxi charged $2.70 per mile, and they paid the dr
shtirl [24]

Answer:

5 miles

Step-by-step explanation:

To find how many miles it is from the train station to the museum we first have to subtract the tip from the total fair and you get 13.50 and then you divide 13.50 by 2.70 to get the number of miles and you get 5.

3 0
2 years ago
5. Write down the nth term of each of the following G.Ps
yawa3891 [41]

Answer:

1i) nth term = 12(-b/4)^(n-1)

ii) nth term = 3(-1/9)^(n-1)

2i) Sixth term= (-3b^5)/256

ii) Eight term = -1/1594323

Question:

The complete question as found on brainly (question-10746111):

Write down the nth term of each of the following G.Ps whose first two terms are given as follows. Also find the term stated besides each G.P.

i) 12,-3b,......sixth term

ii) 3,-1/3,..........;8th term?

Step-by-step explanation:

1) To solve terms involving Geometric progressions (GPs), we would first state the variables that are to be incorporated in the formula.

i) 12,-3b,......;sixth term

1st term = a= 12

r = common ratio = 2nd term /1st term

r = -3b/12 = -b/4

Then we would find the nth term

See attachment for details

ii) 3,-1/3,..........;8th term

1st term = a= 3

r = common ratio = 2nd term /1st term

r = (-⅓)/3 = (-⅓)(⅓) = -1/9

Then we would find the nth term

See attachment for details

2) we are to determine the sixth term in (i) and eight term in (ii)

See attachment for details

Sixth term= (-3b^5)/256

Eight term = -1/1594323

7 0
3 years ago
A company find that 4 1/4 % of the tyres are defective. The company made 28,000 tyres. How many tyres were defective?
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Answer:

595 pairs of tyres are defective.

Step-by-step explanation:

4.25×28000

____

100

0.0425×28000

1190 Total no. of defective tyres

1190 divide total tyres by 2 to get the exact pairs of defective tyres.

____

  2  

595 tyresof shoes are defective.

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3 years ago
Suppose Johnny invests $2,745 into an account, which has been earning interest for many years and he now has a total of $39,974.
Ket [755]

Answer:

i don't understand your question

5 0
3 years ago
Read 2 more answers
Help with 1 and 2 polygons
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#1 is a pentagon.
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