1 gallon is 128 ounces, 5 gallons is 640 ounces. So 6*16=94 ounces Pitcher equals 64 ounces, so 640-158=452, there are 452 ounces of water left
Answer: the answer is C
Step-by-step explanation:
U R welcome
Mark brainliest
Answer:
The equation would be y + 1 = 3(x + 1)
Step-by-step explanation:
In order to find the equation of this line, we have to use the slope formula to find the slope.
m (slope) = (y2 - y1)/(x2 - x1)
m = (3 - -3)/(2 - 0)
m = (3 + 3)/(2 - 0)
m = 6/2
m = 3
Now that we have that, we can use it along with the second point to put into the point-slope equation.
y - y1 = m(x - x1)
y - -1= 3(x - -1)
y + 1 = 3(x + 1)
What is the outlier in the following data set:<br>
15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya
Step-by-step explanation:
The steps to find an outlier:
1. Put the data in numerical order.
2. Find the median.
3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.
The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.
4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.
5. Multiply...1.5 * IQR
6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.
7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.
For your data....the median, Q2 is
(43+38)/2 = 40.5.
Q1 = (30+26)/2 = 28.
Q3 = (54+52)/2 = 53
The IQR is 53 - 28 = 25
1.5 * IQR = 37.5
Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.
Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.
My conclusion is that there are no outliers in this data.
I hope this helps!
Step-by-step explanation:
11.42
