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EleoNora [17]
3 years ago
10

What is the simplified form of the seventh root of x times the seventh root of x times the seventh root of x times the seventh r

oot of x
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0
X^(1/7)x^(1/7)x^(1/7)x^(1/7)

Well the rule for multiplying similar bases with exponents is:

(a^b)(a^c)(a^d)=a^(b+c+d), so in this case:

x^(1/7+1/7+1/7+1/7)

x^(4/7)

In words that is x raised to the 4/7 th power or the seventh root of x raised to the 4th power.
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−k+2(−2k−5) simplify
Agata [3.3K]

Answer:

-k-14

Step-by-step explanation:

Use distributive property and then just carry on and combine like terms.

5 0
2 years ago
Read 2 more answers
Integrate cosx/sqrt(1+cosx)dx
Step2247 [10]
<span>Take the integral: integral (cos(x))/sqrt(cos(x)+1) dx
For the integrand (cos(x))/sqrt(1+cos(x)), substitute u = 1+cos(x) and du = -sin(x) dx: = integral (u-1)/(sqrt(2-u) u) du
For the integrand (-1+u)/(sqrt(2-u) u), substitute s = sqrt(2-u) and ds = -1/(2 sqrt(2-u)) du: = integral -(2 (1-s^2))/(2-s^2) ds
Factor out constants: = -2 integral (1-s^2)/(2-s^2) ds
For the integrand (1-s^2)/(2-s^2), cancel common terms in the numerator and denominator: = -2 integral (s^2-1)/(s^2-2) ds
For the integrand (-1+s^2)/(-2+s^2), do long division: = -2 integral (1/(s^2-2)+1) ds
Integrate the sum term by term: = -2 integral 1/(s^2-2) ds-2 integral 1 ds
Factor -2 from the denominator: = -2 integral -1/(2 (1-s^2/2)) ds-2 integral 1 ds
Factor out constants: = integral 1/(1-s^2/2) ds-2 integral 1 ds
For the integrand 1/(1-s^2/2), substitute p = s/sqrt(2) and dp = 1/sqrt(2) ds: = sqrt(2) integral 1/(1-p^2) dp-2 integral 1 ds
The integral of 1/(1-p^2) is tanh^(-1)(p): = sqrt(2) tanh^(-1)(p)-2 integral 1 ds
The integral of 1 is s: = sqrt(2) tanh^(-1)(p)-2 s+constant
Substitute back for p = s/sqrt(2): = sqrt(2) tanh^(-1)(s/sqrt(2))-2 s+constant
Substitute back for s = sqrt(2-u): = sqrt(2) tanh^(-1)(sqrt(1-u/2))-2 sqrt(2-u)+constant
Substitute back for u = 1+cos(x): = sqrt(2) tanh^(-1)(sqrt(sin^2(x/2)))-2 sqrt(1-cos(x))+constant
Factor the answer a different way: = sqrt(1-cos(x)) (csc(x/2) tanh^(-1)(sin(x/2))-2)+constant
Which is equivalent for restricted x values to:
Answer: | | = (2 cos(x/2) (2 sin(x/2)+log(cos(x/4)-sin(x/4))-log(sin(x/4)+cos(x/4))))/sqrt(cos(x)+1)+constant</span>
3 0
3 years ago
What side lengths form a right triangle?<br> It says I need more than 1 answer
maria [59]
Answer: A and C
Ecplanation: photo
7 0
2 years ago
What ratio is equivalent to 21/35
eimsori [14]
A 2:5 ratio. Because 21 divided by 7 equals 3 and 35 divided by 7 equals 5. And I did it by 7 because thats common factor
4 0
2 years ago
the height of a cylinder is three times the diameter of the base . The surface area of thre ylinder is 126pi ft^2. What is thr r
Over [174]
The answer is 3 ft

The surface area (SA) of a cylinder with radius r and height h is:
SA = 2πr² + 2πrh = π(2r² + 2rh)

We have:
SA = 126π ft²
h = 3 * d
d = 2r
h = 3 * 2r = 6r

126π = π(2r² + 2rh)
126 = 2r² + 2rh
126 = 2r² + 2r * 6r
126 = 2r² + 12r²
126 = 14r²
r² = 126/14
r² = 9
r = √9
r = 3
8 0
3 years ago
Read 2 more answers
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