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3 years ago

Convert 15/50 to a percent.A)0.3%B)3.0%C)30%

Mathematics

1 answer:

In-s [12.5K]3 years ago

5 0

Multiply 0.3 by 100 to convert to a percentage. 0.3⋅100.

Simplify 0.3⋅100 0.3 ⋅ 100 .

Your answer is C.) 30%

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4x + 7 = 23slove this

Juli2301 [7.4K]

Given:

4x + 7 = 23

Let's solve for x.

First Step:

Subtract 7 from both sides

4x + 7 - 7 = 23 - 7

4x = 16

Next Step:

DIvide both sides by 4

$\begin{gathered} \frac{4x}{4}=\frac{16}{4} \\ \\ x\text{ = 4} \end{gathered}$

ANSWER:

x = 4

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10 months ago

If the ratio of boys to girls in the sixth-grade chorus is 2 to 3, which choice shows possible numbers of the boys and girls in

loris [4]

Answer:

4 to 6

Step-by-step explanation:

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2 years ago

For the function: g(x)= 3 - 8 (1/4)^2-x

Alla [95]

Answer:

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Step-by-step explanation:

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2 years ago

Prescription for marilyn jones

sattari [20]

Answer:

The pharmacy should give Marilyn 135 tablets to fill the isoniazid for 45 days

Step-by-step explanation:

Marilyn has to take isoniazid 100 milligrams tablet 3 times a day which means three tablets a day.

The pharmacy has to provide the tablets for 45 days

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2 years ago

Eddi Din [679]

Answer:

a) $y=\dfrac{5}{2}x$

b) yes the two lines are perpendicular

c) $y=\dfrac{5}{4}x+6$

Step-by-step explanation:

a) All this is asking if to find a line that is perpendicular to 2x + 5y = 7 AND passes through the origin.

so first we'll find the gradient(or slope) of 2x + 5y = 7, this can be done by simply rearranging this equation to the form $y = mx + c$

$5y = 7 - 2x$

$y = \dfrac{7 - 2x}{5}$

$y = \dfrac{7}{5} - \dfrac{2}{5}x$

$y = -\dfrac{2}{5}x+\dfrac{7}{5}$

this is changed into the $y = mx + c$ , and we easily see that -2/5 is in the place of m, hence $m = \frac{-2}{5}$ is the slope of the line 2x + 5y = 7.

Now, we need to find the slope of its perpendicular. We'll use:

$m_1m_2=-1$ .

here both slopes $m_1$ and $m_2$ are slopes that are perpendicular to each other, so by plugging the value -2/5 we'll find its perpendicular!

$\dfrac{-2}{5}m_2=-1$ .

$m_2=\dfrac{5}{2}$ .

Finally, we can find the equation of the line of the perpendicular using:

$(y-y_1)=m(x-x_1)$

we know that the line passes through origin(0,0) and its slope is 5/2

$(y-0)=\dfrac{5}{2}(x-0)$

$y=\dfrac{5}{2}x$ is the equation of the the line!

b) For this we need to find the slopes of both lines and see whether their product equals -1?

mathematically, we need to see whether $m_1m_2=-1$ ?

the slopes can be easily found through rearranging both equations to $y=mx+c$

Line:1

$2x + 3y =6$

$y =\dfrac{-2x+6}{3}$

$y =\dfrac{-2}{3}x+2$

Line:2

$y = \dfrac{3}{2}x + 4$

this equation is already in the form we need.

the slopes of both equations are

$m_1 = \dfrac{-2}{3}$ and $m_2 = \dfrac{3}{2}$

using

$m_1m_2=-1$

$\dfrac{-2}{3} \times \dfrac{3}{2}=-1$

$-1=-1$

since the product does equal -1, the two lines are indeed perpendicular!

c)if two perpendicular lines have the same intercept, that also means that the two lines meet at that intercept.

we can easily find the slope of the given line, y = − 4 / 5 x + 6 to be $m=\dfrac{-4}{5}$ and the y-intercept is $c=6$ the coordinate at the y-intercept will be (0,6) since this point only lies in the y-axis.