Answer:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Step-by-step explanation:
The area for a rectangle is given by the formula:

Where <em>w</em> is the width and <em>l</em> is the length.
We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.
First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>
![\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bw%5Cell%5D)
By the Product Rule:

Since we know that dl/dt = 6 and that dw/dt = 5:

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Answer:
x is 16
Step-by-step explanation:
Multiply the 2/5 by 8/8 and you should get 16/40
Hope this helped!
<h3>
Answer: y = 10</h3>
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Work Shown:
EI = EG
3y-10 = 2y
3y-10-2y = 0
y-10 = 0
y = 0+10
y = 10
Note how if y = 10, then
- EI = 3y-10 = 3*10-10 = 20
- EG = 2y = 2*10 = 20
Both EI and EG are 20 units long when y = 10. This confirms the answer.
Answer:
352,635,000
Step-by-step explanation: