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Elina [12.6K]
3 years ago
9

Uestion: How much interest is earned from $1,300 invested at a simple interest rate of 7.75%

Mathematics
1 answer:
Simora [160]3 years ago
3 0

Answer:

$302.25

Step-by-step explanation:

First, change 7.75% into the decimal form. The work is shown below:

7.75% -> \frac{7.75}{100} -> 0.0775

Using the equation I=Prt, lets plug in the values.:

I=1,300(0.0775)(3)

I=302.25

$302.25 worth of interest was earned after 3 years.

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Answer:

x = 127°

Step-by-step explanation:

in each triangle, the value of each exterior angle is equal to the sum of its two non-adjacent interior angles..

47° + 80° = 127°

or

the third angle in the triangle:

180° - (47° + 80°) = 53°

exterior angle:

180° - 53° = 127°

7 0
3 years ago
Read 2 more answers
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
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3 years ago
A game is played with a circular spinner that contains 8 different colors. The design
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Answer:

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forsale [732]

Answer:

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<h3>1.</h3>

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  n ≤ 2 . . . . . . . divide by 7

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The solution is n ≤ -2 or n ≥ 8.

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Answer:


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