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2 years ago

For which k is it true that the sum of k consecutive integers is always divisible by k?

Mathematics

1 answer:

nevsk [136]2 years ago

5 0

Answer:

Step-by-step explanation:

We have two consecutive even integers:

a and b.

We know that we can write a even integer as:

a = 2*n

where n is an integer.

Then the consecutive integer to a, b, will be:

b = 2*n + 2.

Then the sum of a and b is:

a + b = 2n + 2n + 2 = 4*n + 2 = 2*(2n + 1) = k.

The next two consecutive integers greater than b will be:

c = 2n + 4

d = 2n + 6

then:

c + d = (2n + 4) + (2n + 6) = 4n + 10 = k + 4.

I hope i helped:D

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Amanda goes to a football game with 2

PtichkaEL [24]

Answer:

99.25

Step-by-step explanation:

3 times 25.50 = 76.5

2 times 4.75 =

3 times 2.25 = 6.75

3.5 + 3 + 76.5 + 9.5 + 6.75 = 99.25

In total, they spent $99.25 at the football game.

3 0

3 years ago

Read 2 more answers

Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2

inna [77]

$(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)$

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

$6 x^{6}/3x = 2 x^{5} \\ \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\$

We repeat previous steps until we run out of numbers:
$3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2$
$\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}$

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
$(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )$

6 0

3 years ago

On a map, 9 cm represents 15 miles. If the distance between two cities on the map is 15 cm, how many miles separate the cities?

torisob [31]

Answer:

15 cm on the map is equal to 25 miles.

Step-by-step explanation:

Given that,

On a map, 9 cm represents 15 miles.

The distance between two cities is 15 cm. We need to find the distance in miles.

9 cm = 15 miles

$1\ cm=\dfrac{15}{9}\ \miles$

So, 15 cm is equal to,

$15\ cm=\dfrac{15}{9}\times 15\ miles\\\\=25\ miles$

So, 15 cm on the map is equal to 25 miles.

4 0

3 years ago

The answer with an explanation please

ValentinkaMS [17]

Answer:

Step-by-step explanation:

5) C because median is the middle of the set of numbers source A median is 4 source B median is 6 and 4 is 2 less than 6.

6) C because there are 6 numbers altogether and 1 6s on a dice so 6+6 because we have two dice and 2 6s on both so 2/12 or simplified 1/6

7) D because mean is all the numbers add up divided by the amount of numbers so 20+25+30+20+30 = 125 and 125 ÷ 5 = 25

8 B because mean is all the numbers add up divided by the amount of numbers so

5+6+7+8+8+8+8+8+8+9+9 = 76 ÷ by 10 is 7.6

7+7+7+7+8+8+8+8+10+10 = 80 ÷ by 10 = 8

8 + 7.6 = 15.6 ÷ 2 = 7.8 and B is closest to 7.8

4 0

3 years ago

HLEPPPPPP!!!!!

Ksenya-84 [330]

Answer:

Solutions:-5,0,9,6

Not solutions: 12.5,10

Explanation:

The inequality that was given is:

20 > 5 + 3x

First, group similar terms;

20 - 5 < 3x

15 < 3x

x = 5

Thus, the solutions are:-3.5, 5, 4 3/4, -15

The not solutions are:-10 2/3, 129,

Hope this helps! :)

7 0

3 years ago