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Vlada [557]
2 years ago
8

You own 6 hats and are taking 2 on vacation. In how many different ways can you choose 2 hats from 6

Mathematics
2 answers:
vaieri [72.5K]2 years ago
7 0

Answer: 15 ways.


Step-by-step explanation:

Total number of hats owned =6

The number of hats taking on vacation=2

To find the different ways to choose 2 hats from 6, we use combination with n=6 and r=2, we get

The number of ways to choose 2 hats from 6=^nC_r=^6C_2

=\frac{6!}{(6-2)!2!}\\\\=\frac{6\times5\times4!}{4!\times2!}\\\\=\frac{6\times5}{2}\\\\=3\times5=15\ \text{ways}

Hence, in 15 ways we can choose 2 hats from 6 hats.

Alex_Xolod [135]2 years ago
3 0
Hats 1,2,3,4,5,6
1,2
1,3
1,4
1,5
1,6
2.3
2,4
2,5
2,6
3,4
3,5
3,6
4,5
4,6
5,6

15 different combinations 
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8-35. Use your knowledge of polygons to answer the questions below, if possible.
Nataliya [291]

Answer:

(a)I. 13 Sides II. 7 Sides

(b) 4 Sides, Square

(c)x=52 degrees

(d)x=107 degrees

(e)1620 degrees

Step-by-step explanation:

(a)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

I. If the Interior angle is 1980^0

Then:

(n-2)180^0=1980^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=11\\$Add 2 to both sides of the equation\\n-2+2=11+2\\n=13

The polygon has <u>13 sides.</u>

II. If the Interior angle is 900^0

Then:

(n-2)180^0=900^0\\$Divide both sides by 180^0 $ to isolate n$\\n-2=5\\$Add 2 to both sides of the equation\\n-2+2=5+2\\n=7

The polygon has <u>7 sides.</u>

(b)The sum of the exterior angle of a polygon is 360 degrees,

Each exterior angle of a n-sided regular polygon is: \frac{360^0}{n}

If the exterior angle of a regular polygon is 90°

Then:

90\°=\frac{360^0}{n}\\ 90n=360\\n=4

The regular polygon has 4 sides and it is called a <u>Square.</u>

<u>(c)</u>The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

Each Interior angle of a regular n-sided polygon is:  \frac{(n-2)180^0}{n}

For a pentagon, n=5

Then:

\frac{(5-2)180^0}{5}=2x+4\\108=2x+4\\108-4=2x\\104=2x\\x=52^0

(d)The <u>sum of the exterior angle of a polygon is 360 degrees.</u>

If four of the exterior angles of a pentagon are 57, 74, 56, and 66.

Let the fifth angle=x

Then:

57+74+56+66+x=360^0\\253+x=360\\x=107^0

(e)The Sum of the Interior angle of polygon with n sides is derived using the formula: (n-2)180.

In an 11-gon., n=11

Therefore, the sum of the interior angle=(11-2)180=1620^0

The sum of the interior angle <u>does not change either in a regular or irregular polygon.</u>

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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