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iogann1982 [59]
3 years ago
14

Write in radical form

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0

Step-by-step explanation:

I'll do one for you.

Using the formula for turning exponents into radicals

(b) {}^{ \frac{x}{y} }  =    \sqrt[y]{b} {}^{x}

where b is the base

This means that the numerator in the exponet form becomes the power under the radical in radical form and

the denominator in exponet form becomes the nth root in radical form.

For example 5,

(5) {}^{ \frac{ - 3}{5} }

That becomes in radical form

\sqrt[5]{5 {}^{ - 3} }

or if you want to write it using positive exponents

\frac{1}{ \sqrt[5]{5 {}^{3} } }

I'll do one more for you

For example 6,

11 {}^{ \frac{4}{3} }

That becomes in radical form

\sqrt[3]{11 {}^{4} }

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A car depreciates in value by 17% per year.
otez555 [7]

Answer:

17%of 23000

17/100×23000

1 yrs depreciation is 3910

then

after 4 years depreciation is 4×3910

=15640

the worth of after 4 yrs is 23000-15640

=Rs 7360

7 0
2 years ago
6x+32=−2x
velikii [3]
Whatever you do to one side, you have to do to the other.
Try to get all the x values and regular values together.
To do that, just subtract both sides by 6x to cancel it out on one side and subtract it from the other side:

6x-6x+32=-2x-6x
=
32=-8x
now divide both sides by -8 to get the x by itself

32/-8=-8/-8x
= 32/-8=x
-4=x
so your answer is: x= -4
5 0
3 years ago
72 348 675 125 what is the value of the 2 in 72
Masja [62]
2 Billion Is The Value
4 0
3 years ago
Line AB and line BC form a right angle at point B. If A = (-3, -1) and B + (4, 4), what is the equation of line BC?
Andrej [43]

Answer:

C.) -7x - 5y = -48

Step-by-step explanation:

slope AB = (y2 - y1)/(x2-x1)

= {4-(-1)}/{4-(-3)} = 4+1/4+3 = 5/7

slope of BC = -1 ÷ 5/7 = -1 × 7/5 = -7/5

taking -7x - 5y = -48

-5y = 7x -48

y = 7x/-5 - 48

y = -7/5x -48

7 0
3 years ago
3 (x+6) what is the answer ??​
ziro4ka [17]

Answer:

3x+18

Step-by-step explanation:

3 (x+6)

Distribute

3x+3*6

3x+18

4 0
2 years ago
Read 2 more answers
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