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3 years ago

11

The label on Emma's muffin said that one serving provided 6 grams of fat, which is 10% of the recommended daily amount. What is

the total recommended daily amount of fat?

1 answer:

valentina_108 [34]3 years ago

4 0

0.6 because 6 divided by 10% is 0.6

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Select the correct answer

Tasya [4]

The correct answer is the 5th option (one before the last one).

7 0

3 years ago

Look at the picture below

Lelu [443]

Answer: Phillip is correct. The triangles are <u>not </u>congruent.

How do we know this? Because triangle ABC has the 15 inch side between the two angles 50 and 60 degrees. The other triangle must have the same set up (just with different letters XYZ). This isn't the case. The 15 inch side for triangle XYZ is between the 50 and 70 degree angle.

This mismatch means we cannot use the "S" in the ASA or AAS simply because we don't have a proper corresponding pair of sides. If we knew AB, BC, XZ or YZ, then we might be able to use ASA or AAS.

At this point, there isn't enough information. So that means John and Mary are incorrect, leaving Phillip to be correct by default.

Note: Phillip may be wrong and the triangles could be congruent, but again, we don't have enough info. If there was an answer choice simply saying "there isn't enough info to say either if the triangles are congruent or not", then this would be the best answer. Unfortunately, it looks like this answer is missing. So what I bolded above is the next best thing.

7 0

3 years ago

Read 2 more answers

Can Someone Evaluate This

Murrr4er [49]

The answer is B. 9
Hope this helps

6 0

3 years ago

Read 2 more answers

10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the

Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

$H_0: \mu = 0$

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

$H_1: \mu > 0$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

In this problem, the parameters are given as follows:

$\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50$ .

Hence, the test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}$

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by $t^{\ast} = 2.4$ .

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

topjm [15]

Answer: B. neither

<u>Step-by-step explanation:</u>

A function is even when f(x) = f(-x).

A function is odd when f(-x) = -f(x).

f(x) = 2x³ - x²

f(-x) = 2(-x)³ - (-x)²

= -2x³ - x²

f(x) = 2x³ - x² ≠ f(-x) = -2x³ - x² so it is NOT EVEN

-f(x) = -(2x³ - x²)

= -2x³ + x²

f(-x) = -2x³ - x² ≠ -f(x)= -2x³ + x² so it is NOT ODD

Therefore, it is NEITHER even nor odd.

5 0

3 years ago