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lozanna [386]
3 years ago
7

A quadratic function passes through the points ( − 5 , − 8 ) and ( 8 , − 8 ) . Find the equation for the line (axis) of symmetry

.
Mathematics
1 answer:
ra1l [238]3 years ago
8 0

Answer:

The equation for the axis of symmetry is x=1.5.

Step-by-step explanation:

It is given that a quadratic function passes through the points ( − 5 , − 8 ) and ( 8 , − 8 ) .

In the given points y-coordinates are same, i.e., -8. It means both the points lie on the horizontal line y=-8.

If a quadratic function passes through two points (a,c) and (b,c), then the equation for the axis of symmetry is

x=\frac{a+b}{2}

According to the given points a=-5, b=8 and c=-8. Put these value in the above formula.

x=\frac{-5+8}{2}

x=\frac{3}{2}

x=1.5

Therefore the equation for the axis of symmetry is x=1.5.

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Answer:

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Step-by-step explanation:

Since it gives you x, you need to plug in the number given for it into the equation:

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Graph g(x)=2+|x| and it’s parent functions
matrenka [14]

The parent function is ...

... f(x) = |x|

This is the absolute value function, equal x when x ≥ 0, and equal to -x when x < 0. Its graph has the shape of a V with the vertex at the origin and "legs" of slope ±1.

The function g(x) is the same function with 2 added. The addition of 2 moves every value of f(x) up 2 units, so translates the whole graph upward by 2 units.

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3 years ago
Factor 6x4 – 5x2 + 12x2 – 10 by grouping. What is the resulting expression?
Vadim26 [7]

Answer:

(6x² - 5)(x² + 2)

Step-by-step explanation:

Given

6x^{4} - 5x² + 12x² - 10 ( factor the first/second and third/fourth terms )

= x²(6x² - 5) + 2(6x² - 5) ← factor out (6x² - 5) from each term

= (6x² - 5)(x² + 2)

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3 years ago
Read 2 more answers
f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
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