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2 years ago

If Ashton drives 228 miles in 6 hours, what is his unit rate?

Mathematics

2 answers:

Artist 52 [7]2 years ago

6 0

Answer:

The unit rate would be 38 miles per hour

Step-by-step explanation:

If you divide 228 by 6 you would get 38 and to further prove this do 38 x 6 and your answer would be 228

lara31 [8.8K]2 years ago

4 0

228 divide by 6 = 38
38 miles per hour

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How do you simplify(n!)^2/(n+1)!(n-1)!

ANTONII [103]

We haven n! = (n-1)! x n and (n+1)! = n! x (n + 1);
Then, (n!)^2 = n! x n! = n! x (n-1)! x n;
And (n+1)!(n-1)! = n! x (n + 1) x (n-1)!;
Finally, [n! x (n-1)! x n] / [n! x (n + 1) x (n-1)!] = (n+1)/n;

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2 years ago

A manufacturer samples 100 wires for quality testing. 4 wires were found defective. if 750 were produced in 1 hour how many shou

Andreyy89

30 wires would be defective

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3 years ago

The edges of the diameter of a circle are at (-1,2) and (3,-1). Write the equation of the circle in general form.

Y_Kistochka [10]

Answer:

(x-1)²+ (y-0.5)²=6.25

Step-by-step explanation:

The standard form of equation of a circle is;

(x-a)²+(y-b)²=r² where (a,b) are the center of the circle and r is the radius

Finding the mid-point of the given points

(-1,2) and (3,-1)⇒midpoint will be 1/2(x₁+x₂) , 1/2(y₁+y₂)

midpoint= {1/2(-1+3), 1/2(2+-1)}

midpoint=(1,0.5)

Finding the radius r; the distance from the center to either of the given two points

Apply the distance formula d=√ (x₂-x₁)² +(y₂-y₁)²

Taking (x₁,y₁) as (1,0.5) and (x₂,y₂) as (-1,2) then

d=√ (-1-1)² +(2-0.5)²

d= √ (-2)²+(1.5)²

d=√4+2.25⇒√6.25⇒2.5

r=2.5

Equation of the circle

(x-1)² + (y-0.5)²=2.5²

(x-1)²+ (y-0.5)²=6.25

3 0

2 years ago

Heya!

Masteriza [31]

Hello Again! :)

This time I got the correct answer, for you this time....

$Jace$ $is$ $here$ $to$ $hel$ $^{p}$ :

⋆┈┈｡ﾟ❃ུ۪ ❀ུ۪ ❁ུ۪ ❃ུ۪ ❀ུ۪ ﾟ｡┈┈⋆

$The$ $answer$ $to$ $this$ $is$ :

᠃ ⚘᠂ ⚘ ˚ ⚘ ᠂ ⚘ ᠃

⋆ Proof, is shown below of the question:

Hope It Helped! :)

And Tell me if the answer is wrong. . .

Good Luck With Your Assignment!

#LearnWithBrainly

$Answer$ :

Jace ☆

6 0

2 years ago

If x^2y-3x=y^3-3, then at the point (-1,2), (dy/dx)?

zavuch27 [327]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2866883

_______________

 dy
Find —— for an implicit function:
 dx

x²y – 3x = y³ – 3

First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

$\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\
\mathsf{\dfrac{d}{dx}(x^2 y)-3\,\dfrac{d}{dx}(x)=\dfrac{d}{dx}(y^3)-\dfrac{d}{dx}(3)}$

Applying the product rule for the first term at the left-hand side:

$\mathsf{\left[\dfrac{d}{dx}(x^2)\cdot y+x^2\cdot \dfrac{d}{dx}(y)\right]-3\cdot 1=3y^2\cdot \dfrac{dy}{dx}-0}\\\\\\
\mathsf{\left[2x\cdot y+x^2\cdot \dfrac{dy}{dx}\right]-3=3y^2\cdot \dfrac{dy}{dx}}$

 dy
Now, isolate —— in the equation above:
 dx

$\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\
\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3-3y^2\cdot \dfrac{dy}{dx}=0}\\\\\\
\mathsf{x^2\cdot \dfrac{dy}{dx}-3y^2\cdot \dfrac{dy}{dx}=-\,2xy+3}\\\\\\
\mathsf{(x^2-3y^2)\cdot \dfrac{dy}{dx}=-\,2xy+3}$

$\mathsf{\dfrac{dy}{dx}=\dfrac{-\,2xy+3}{x^2-3y^2}\qquad\quad for~~x^2-3y^2\ne 0}$

Compute the derivative value at the point (– 1, 2):

x = – 1 and y = 2

$\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{-\,2\cdot (-1)\cdot 2+3}{(-1)^2-3\cdot 2^2}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{4+3}{1-12}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{7}{-11}}\\\\\\\\ \therefore~~\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=-\,\dfrac{7}{11}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: implicit function derivative implicit differentiation chain product rule differential integral calculus

6 0

2 years ago