Answer:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
Out of 100 people sampled, 42 had kids.
This means that 
99% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).
Answer:
17
Step-by-step explanation:
Let the larger number be represented by x
Let the smaller number be represented by y
from the question, the next equations can be gotten :
x - y = 9 equation 1
x = 1 + 2y equation 2
Substitute for x in equation 1
1 + 2y - y = 9
1 + y = 9
Collect like terms
y = 9 - 1
y = 8
Substitute for y in equation 1 and solve for x (the larger number)
x - 8 = 9
x = 9 + 8
x = 17
5x+30- 2x+9
3x+39 is the expression.
Answer:
not an answer but how do you attach images because it would be more useful
Step-by-step explanation:
