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3 years ago

Rachel took $100 shopping. She spent $37.85 on a new outfit and $42.70 on shoes. How much change did she bring home?

Mathematics

1 answer:

katrin2010 [14]3 years ago

8 0

She bring home is $80.55

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Ms. Canton has a book case. On three of the shelves there are the same amount of books. On another shelf there are four of her f

andrey2020 [161]

Answer:

y = 3x + 4

Step-by-step explanation:

According to the given question, the expression to represent all the books in Ms. Canton's bookcase is shown below:-

y indicates the total amount of books

x indicates the equal cost of books on 3 bookshelves

while

+4 indicates 4 other books on the fourth bookshelf

So, the expression will be

y = 3x + 4

Therefore the correct answer is y = 3x + 4

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3 years ago

What is the solution to x 4 + 4x 3 ≤ 12x 2?

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Answer:

-6,2

Step-by-step explanation:

im not sure what the answer is

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I have another question I'm struggling with. How do I solve to find the missing angle?

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Answer:

$23465459544 + 44492711 = 597595855122256.56114163174112113 \leqslant \leqslant \geqslant yhy \times \frac{?}{?}kwwkjuujsjkoodji \beta \pi \beta \cos(2216 {59 \times \tim3.5es - = 6 \\ \\ 53 \times }^{2} )$

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3 years ago

.. Which of the following are the coordinates of the vertices of the following square with sides of length a?

atroni [7]

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Step-by-step explanation:

Option A: $O(0,0), S(0,a), T(a,a), W(a,0)$

To find the sides of a square, let us use the distance formula,

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,a), T(a,a), W(a,0)$ has sides of length a.

Option B: $O(0,0), S(0,a), T(2a,2a), W(a,0)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

This is not a square because the lengths are not equal.

Option C: $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$

Now, we shall find the length of the square,

$\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}$

Thus, the square with vertices $O(0,0), S(0,2a), T(2a,2a), W(2a,0)$ has sides of length 2a.

Option D: $O(0,0), S(a,0), T(a,a), W(0,a)$

Now, we shall find the length of the square,

$\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}$

Thus, the square with vertices $O(0,0), S(a,0), T(a,a), W(0,a)$ has sides of length a.

Thus, the correct answers are option a and option d.

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3 years ago

Trisha drew a pair of line segments starting from a vertex. Which of these statements best compares the pair of line segments wi

Ksju [112]

The <em>correct answer</em> is:

C) Line segments have two endpoints and a vertex is a common endpoint where two line segments meet.

Explanation:

A line segment is defined as a portion of a line that has two endpoints.

A vertex is defined as the common endpoint of two or more rays or line segments.

This makes C the correct option.

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3 years ago

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