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kogti [31]
3 years ago
11

Find the x-coordinate of the point on the graph of y=x^2 where the tangent line is parallel to the secant line that cuts the cur

ve at x=-1 and x=2
Please how do you solve this?
Mathematics
1 answer:
jek_recluse [69]3 years ago
4 0
First find the secant line. The slope of the secant line through (-1,1) (when x=-1) and (2,4) (when x=2) is the average rate of change of y=x^2 over the interval [-1,2]:

\text{slope}_{\text{secant}}=\dfrac{2^2-(-1)^2}{2-(-1)}=\dfrac33=1

The tangent line to y=x^2 will have a slope determined by the derivative:

y=x^2\implies y'=2x

Both the secant and tangent will have the same slope when 2x=1, or when x=\dfrac12.
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The difference between the set of non-negative real numbers and the set of positive real numbers is:
Inessa05 [86]

Answer:

C; A singleton set

Step-by-step explanation:

Mathematically, when a number is non-negative; it is either positive or zero

Now, this is because 0 identifies as neither a positive or a negative number

hence, when we find the difference between the two sets, the only number that stands out unmatched is the value 0

What this mean is that we are having a set with a single number result

So we have our answer as {0}

Which is a singleton set

4 0
3 years ago
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Svetllana [295]
D. is the answer

y - y1 = m(x - x1)
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Answer: 27

Step-by-step explanation:

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What is the answer to 10 less than 38 is
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