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AveGali [126]
3 years ago
10

What is the area of the trapezoid shown below?

Mathematics
2 answers:
valentina_108 [34]3 years ago
7 0

Answer:

C. 78 sq. units

Step-by-step explanation:

area \: of \: trapezoid \\=  \frac{1}{2}  \times (19 + 7) \times 6 \\  = 26 \times 3 \\  = 78 \: sq \: units

Olegator [25]3 years ago
5 0

Answer:

78

Step-by-step explanation:

7+8/2 multiply by 6

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mestny [16]
Mabel spends 4 hours editing a 3 minute video. she edits at a constant rate. how long does mabel spend to edit a 9 minute video?

she spends 4 hours on a 3 minute video
so there are 60 minutes in an hour
4 hours with 60 minutes- 4x60=240
so she spent 240 minutes on a 3 minute video
3 divided by 240
3/240= 0.0125
so her constant rate is 0.0125 minutes an hour
so divide 9 minutes by her constant rate
9/0.0125 = 720
so she spends 720 minutes on a 9 minute video.
divide 720 by 60 since there are 60 minutes in an hour
720/60 = 12
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7 0
3 years ago
What is the answer to 56-4
Scilla [17]

Answer:

The answer is 52.

Step-by-step explanation:

Subtract 56 by 4. You'll get 52.

5 0
3 years ago
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You are given a loaded six-sided die. Such a die can produce any integer from 1 to 6. The die rolls a 4 three times as often as
beks73 [17]
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6 0
3 years ago
The number 360 is increased by 25%. The result is then decreased by 50%. What is the final number?
Vladimir [108]
So if 360 is increased by 25%, you would end up with 450 (360 x 1.25), than if the result, 450 is decreased by 50% ( 450 x .50 = 225) (450 - 225 = 225) you would end up with 225.
3 0
3 years ago
Need help #1. The answer is shown, but I don’t know how to get to the answer. Please teach and show steps.
Rufina [12.5K]

Answer:

B

Step-by-step explanation:

We are given that <em>x</em> and <em>y</em> are functions of time <em>t</em> such that <em>x</em> and <em>y</em> is a constant. So, we can write the following equation:

x(t)+y(t)=k,\text{ where $k$ is some constant}

The rate of change of <em>x</em> and the rate of change of <em>y</em> with respect to time <em>t</em> is simply dx/dt and dy/dt, respectively. So, we will differentiate both sides with respect to <em>t: </em>

<em />\displaystyle \frac{d}{dt}\Big[x(t)+y(t)\Big]=\frac{d}{dt}[k]<em />

Remember that the derivative of a constant is always 0. Therefore:

\displaystyle \frac{dx}{dt}+\frac{dy}{dt}=0

And by subtracting dy/dt from both sides, we acquire:

\displaystyle \frac{dx}{dt}=-\frac{dy}{dt}

Hence, our answer is B.

3 0
3 years ago
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