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alex41 [277]
3 years ago
13

A cylinder has a base with a diameter of 10.8 centimeters and height 15 centimeters. Enter the volume of the cylinder, in cubic

centimeters. Round your answer to the nearest hundredth
Geography
1 answer:
Yuri [45]3 years ago
7 0

Answer:

Volume\ of\ cylinder=1373.43\ cm^3\ \ \ \ \ \ \ \ \ \ \ (taking\ \pi=3.14)

Explanation:

Volume of cylinder: Volume=\pi (radius)^2height

Diameter\ of\ the\ base=10.8\ cm\\\\radius=\frac{diameter}{2}\\\\Radius=\frac{10.8}{2}\\\\Radius(r)=5.4\ cm\\\\Height(h)=15\ cm\\\\Volume\ of\ cylinder=\pi r^2h\\\\Volume\ of\ cylinder=3.14\times (5.4)^2\times 15\\\\Volume\ of\ cylinder=3.14\times 29.16\times 15\\\\Volume\ of\ cylinder=1373.43\ cm^3

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The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

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\Delta t = \frac{s}{v} (1)

Where:

s - Travelled distance, measured in kilometers.

v - Speed of the passenger aircraft, measured in kilometers per second.

\Delta t - Travelling time, measured in seconds.

If we know that s = 1.496\times 10^{8}\,km and v = 0.45\,\frac{km}{s}, then the travelling time is:

\Delta t = \frac{1.496\times 10^{8}\,km}{0.45\,\frac{km}{h} }

\Delta t = 3.324\times 10^{8}\,s

\Delta t = 3847.736\,days

\Delta t = 10.542\,years

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The distance between the Earth and the galactic center is approximately equal to 2.460\times 10^{17}\,km. If the passenger travels at constant speed and if we know that s = 2.460\times 10^{17}\,km and v = 0.45\,\frac{km}{s} , then the travelling time is:

\Delta t = \frac{2.460\times 10^{17}\,km}{0.45\,\frac{km}{s} }

\Delta t = 5.467\times 10^{17}\,s

\Delta t = 6.327\times 10^{12}\,days

\Delta t = 1.733\times 10^{10}\,years

The passenger aircraft would take 1.733\times 10^{10} years to reach the gallactic center.

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