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levacccp [35]
3 years ago
12

2. Gas exchange occurs in the bark through light and dark disruptions called:

Biology
2 answers:
LiRa [457]3 years ago
6 0

Answer:

B

Explanation:

Nutka1998 [239]3 years ago
6 0

Answer:

stomata

Explanation:

Stomata is a pure found in the epidermis of leaves, stems, and other organs, that facilitates gas exchange.

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Agouti is a type of coat-color pattern in mice that cannot be expressed in albinos (white mice). Non Albino mice without the dom
damaskus [11]

Answer:

37.5%

Explanation:

These here are

Black (AA or Aa) and albino (aa)

Agouti (Bb or BB)

Thus, a cross between

AaBb and aaBb

The percent of the progeny which are likely to be agouti would be

A. a. B. b

a. Aa. aa. B. BB. Bb

a. Aa. aa. b. Bb. bb

The probability of agouti would be

1/2 (Aa) * 3/4 (BB or Bb)

= 3/8

= 37.5%

5 0
3 years ago
Read 2 more answers
Which constellation is home to the star forming nebula called the heart nebula?
miv72 [106K]
The milky way is your answer
5 0
3 years ago
Effect of water pollution​
PIT_PIT [208]

Destruction of biodiversity. Water pollution depletes aquatic ecosystems and triggers unbridled proliferation of phytoplankton in lakes — eutrophication —. Contamination of the food chain.Human diseases: Pathogens(viruses,bacteria,fungi,protozoa etc)are biological pollutants of water. They cause typhoid,cholera,dysentery,jaundice,hepatitis.

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6 0
3 years ago
Which one of the following is NOT one of the secondary sex characteristics typical of males?
dexar [7]
Development of breast tissue
4 0
3 years ago
In guinea pigs coat color is determined by a single gene with two alleles. A guinea pig from a true-breeding black strain is mat
OLga [1]

Answer:

1/3 of black F2 progeny will be homozygous.

Explanation:

Here, BB = black coat color = true breeding dominant black strain

bb = white coat color =  true breeding recessive white strain

When true breeding black and white guinea pigs are mated to give F1 progeny:

BB X bb = Bb ( all black guinea pigs )

When two of the F1 guinea pigs are mated to give F2 progeny:

Bb X Bb = BB, Bb, Bb, bb

F2 progeny has 3/4 progeny as black (BB and Bb) . Out of them 1/3 are homozygous and 2/3 are heterozygous.

Hence, 1/3 of black F2 progeny will be homozygous.

7 0
3 years ago
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