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kherson [118]
3 years ago
5

Lainey bought a set of 202020 markers for \$6$6dollar sign, 6. What is the cost of 1 marker?

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

$0.30

Step-by-step explanation:

6 / 20

0.3

Best of Luck!

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Radius of a circle is 5 cm
Vesnalui [34]

Answer:

the answer is (b.)41.7cm²

the workings;;

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7 0
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It has been estimated that an adult T. rex weighed about six tons. Based on that estimate. how many pounds did four adult T.rexe
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3 0
3 years ago
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How much money is required to buy 2 cakes of soap at $.18 a cake an 1 dozen eggs at $.65 a dozen
mestny [16]

Answer: 1.01$

Step-by-step explanation:

.18 + .18=.36

.36 + .65=1.01$

8 0
3 years ago
Perform the following computations.You may use13≈0.333333,34= 0.75 and100301= 0.332226.(i). Compute13+34by using five significan
White raven [17]

Answer:

a. 1.0833

Absolute Error = 0.416667

Relative Error = 1.250002

b. 0.0011070

Absolute Error = 0.0011070

Relative Error = 0.003321

Step-by-step explanation:

Given

1/3 = 0.333333

3/4 = 0.75

100/301 = 0.332226

a.

1/3 + 3/4

= 0.333333 + 0.75

= 1.083333

= 1.0833 ------ Approximated to 5 significant digits

Absolute Error = |Real Value - Estimated Value|

Relative Error = Absolute Error/Real Value

Assume 1/3 to be the real value and 3/4 to be the estimated value

Absolute Error = |0.333333 - 0.75|

Absolute Error = |-0.416667|

Absolute Error = 0.416667

Relative Error = 0.416667/0.333333

Relative Error = 1.250002

b.

1/3 - 100/301

= 0.333333 - 0.332226

= 0.001107

= 0.0011070 ----- Approximated to 5 significant digits

Assume 1/3 to be real value and 100/301 to be estimated value

Absolute Error = 0.333333 - 0.332226

Absolute Error = 0.0011070

Relative Error = 0.0011070/0.333333

Relative Error = 0.003321

Absolute and relative errors are approximation errors and they are due to the discrepancy between an exact value and some approximation to them.

The absolute error is the magnitude of the difference between the exact value and the approximation. The relative error is the absolute error divided by the magnitude of the exact value

4 0
3 years ago
A box contains 4 black shirts, 8 blue shirts, 4 black pants, and 10 blue pants. Determine the probability of randomly selecting
Elenna [48]
So there is 26 shirts in total because 4+8+4+10=26 Then you need to take 26-4=22. You do this because there is 26 total clothing and only 4 of them aren't either a blue piece of clothing or pants that means you have 22 pieces of clothing that are blue or pants. So your odds of picking a blue piece of clothing or pants is 22/26. 

Hope this Helps!!
3 0
3 years ago
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