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kherson [118]
3 years ago
5

Lainey bought a set of 202020 markers for \$6$6dollar sign, 6. What is the cost of 1 marker?

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

$0.30

Step-by-step explanation:

6 / 20

0.3

Best of Luck!

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erma4kov [3.2K]
I believe the answer is 8
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Felix says if 2/3 pan of lasagna had been left over from dinner and the padis family ate 1/2 of that for lunch, the answer would
olga_2 [115]

Answer:

He is right he can eat 2/6 f the whole pan of lasagna

Step-by-step explanation:

We had  2/3 pan of lasagna and pads family ate 1/2 of it, then

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2/6 is half of the total pan of lasagna, padis family ate half of 2/3 wich is 2/6 and left 2/6 for Felix

6 0
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If cos θ > 0 and tan θ > 0, which of the following statements MUST be true? (5 points)
solniwko [45]

Yo sup??

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tanx>0 in the 1st and 3rd quadrant.

therefore the common solution is x lies in 1st quadrant.

Hence the correct answer is option A.

Hope this helps

5 0
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A circle is centered on point BBB. Points AAA, CCC and DDD lie on its circumference. If \orange{\angle ADC}∠ADCstart color #ffa5
tiny-mole [99]

Answer:

  122°

Step-by-step explanation:

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Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q2+11q
Sedbober [7]

Answer:

(q+\frac{11}{2})^2-\frac{121}{4}

Step-by-step explanation:

We have been given an expression q^2+11q. We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form a^2+2ab+b^2.

To convert our given expression into perfect square trinomial, we need to add and subtract (\frac{b}{2})^2 from our given expression.

We can see that value of b is 11, so we need to add and subtract (\frac{11}{2})^2 to our expression as:

q^2+11q+(\frac{11}{2})^2-(\frac{11}{2})^2

Upon comparing our expression with (a+b)^2=a^2+2ab+b^2, we can see that a=q, 2ab=11q and b=\frac{11}{2}.

Upon simplifying our expression, we will get:

(q+\frac{11}{2})^2-\frac{11^2}{2^2}

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Therefore, our perfect square would be (q+\frac{11}{2})^2-\frac{121}{4}.

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