Question

Which shows how to find the value of this expression when x = negative 2 and y = 5? (3 x cubed y Superscript negative 2 Baseline) squared

Answer 1

Answer:

$(3x^3y^{-2})^2$ =  $\frac{576}{625}$

Step-by-step explanation:

Given:

$x=-2$

$y=5$

To evaluate:

$(3x^3y^{-2})^2$

Solution:

Applying property of exponents to simplify the expression.

Property: $(a^b)^c= a^{bc}$

So, we have: $(3x^3y^{-2})^2$

⇒ $3^2x^6y^{-4}$

⇒ $9x^6y^{-4}$

Property : $a^{-b}=\frac{1}{a^b}$

⇒ $\frac{9x^6}{y^4}$

Now, plugging in values of $x$ and $y$.

⇒ $\frac{9(-2)^6}{5^4}$

⇒ $\frac{9\times 64}{625}$

⇒ $\frac{576}{625}$     (Answer)

Answer 2

A) 3^2(-2)^6/5^4

I just took the quiz on edge