$y=(1+x)e^{x^2}\\
y'=(1+x)'\cdot e^{x^2}+(1+x)\cdot(e^{x^2})'\\
y'=1\cdot e^{x^2}+(1+x)\cdot e^{x^2}\cdot (x^2)'\\
y'=e^{x^2}+(1+x)e^{x^2}\cdot2x\\
y'=e^{x^2}(1+(1+x)\cdot2x)\\
y'=e^{x^2}(1+2x+2x^2)\\
y'=e^{x^2}(2x^2+2x+1)\\$

5 0

4 years ago

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5x + 2y = 8 How do I solve for y

Inessa05 [86]

Answer:

first, subtract 5x from both sides. now you have 2y = -5x + 8. then divide everything by 2. now you have y = (-5x+8)/2

8 0

3 years ago

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What is the area of the trapezoid below?

wlad13 [49]

Answer:

Step-by-step explanation:

5 0

3 years ago

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When Tyson opens and lays a cereal box out flat, he sees that the top and bottom of the box each measure 3 inches by 9 inches, t

slega [8]

Answer:

Step-by-step explanation:

4 0

3 years ago