The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
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Answer:
d
Step-by-step explanation:
5x + 4 = -6
5x= -6-4
5x=-10
x=-2
The value of the first expression is x=-2.
x/2 + 3 = 2
x/2 = 2-3
x/2 = -1
x=-2
The value of the second expression is x=-2.
2x+14=10
2x=-4
x=-2
The value of the third expression is x=-2.
-2=-x
2=x
The value of the fourth expression is x=2.
Answer:
7
Step-by-step explanation:
-4 +11 is saying that assuming if a person owe 4 dollars and his friend gives him 11 dollars that he will pay back the four dollars and still have 7 dollars left
Answer:
Dive by n square root two, also option one.
Step-by-step explanation:
The first step to any algebra equation is to isolate the variable and you do that by divide square root 2 since it cancels out on the left side and now n is alone.
Hoped that helped :)
