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Agata [3.3K]
3 years ago
15

Find the # of possibilities. You are setting the combination on a four-digit lock. You want to use the numbers 1, 2, 3, and 4 bu

t don't care what order they are in. Explain your answer
Mathematics
1 answer:
icang [17]3 years ago
4 0
1234
1243
1432
1324
1423
1342
There's 24 different equations
You might be interested in
No Links
Alecsey [184]

Answer:

8

Explanation:

Since 30 people have already voted, they need 30 more to vote so that they will have 60 votes. Since Devon got 4 votes the first time we will double that to go to 60 votes which than gives you your solution of 8 answer choice B.

4 0
3 years ago
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
Can someone help please ​
Novosadov [1.4K]

Answer: 4/9

Step-by-step explanation:

7 0
3 years ago
Which Expression is equivalent to 5−3(4−1)?
Juliette [100K]
Non of the answers are right because the answer should be equivalent to -4

7 0
3 years ago
What is the domain of the graph? A) 2 < x < 5 B) 2 ≤ x ≤ 5 C) 3 < y < 5 D) 3 ≤ y ≤ 5
Firlakuza [10]

Answer:

A rectangle of dimension 2*3.

Step-by-step explanation:

Draw two lines y=3 and y=5.

Draw two lines x=2 and x=5.

There intersection is rectangle with vertices (2,3), (2,5), (5,3), (5,5)

8 0
3 years ago
Read 2 more answers
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