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juin [17]
3 years ago
11

What is 1.625 rounded to the nearest hundredth

Mathematics
2 answers:
charle [14.2K]3 years ago
8 0
B because the 2 is in the hundredths place and then you look behind the 2 which is a 5.

If its five or more you go up and 4 or less you go down, which means that you add one to the 2 which is 3 and you get rid of anything behind the 3 that was the originally.
Korvikt [17]3 years ago
7 0
1.63
The 1 is in the ones place
The 6 is in the Tenths
The 2 is in the Hundredths place
The 5 is in the thousandths place
When rounding, you take the number to the right of the number to determine if you’re rounding up or down. If the number is 0,1,2,3 or 4 you round down. If it’s 5,6,7,8 or 9 you round up. In this case we round up
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Step-by-step explanation:

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Find a cubic function with the given zeros. Square root of seven. , - Square root of seven. , -4
yan [13]

Answer:

y= x^{3} +4x^{2}-7x-28

Step-by-step explanation:

We have to find a cubic function of x whose zeros are at x = √7, x = -√7 and at x = -4.

Therefore, the factors of the function will be (x - √7), (x + √7), and (x + 4)

Hence, the equation will be y = (x - √7) (x + √7) (x + 4)

⇒ y = (x^{2} -7)(x +4)

⇒ y= x^{3} +4x^{2}-7x-28 (Answer)

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3 years ago
True or False? A rectangle is a quadrilateral with four right angles.
s344n2d4d5 [400]
True is the correct answer.
4 0
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gulaghasi [49]

Answer:

Step-by-step explanation:

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In ΔABC, m∠A = 90° and AN is an altitude. If AB = 20 in and AC = 15 in, find BC, BN, NC, AN.
uranmaximum [27]
Since ΔABC is a right triangle, we can use the Pythagorean theorem to find the missing side, BC as shown below.

\overline{BC}= \sqrt{20^{2} + 15^{2}} = 25

Now, since AN is an altitude formed along BC, we can form two smaller triangles that are both similar with ΔABC.
(An image is attached along the file to show the illustrations of the triangles with the larger one.)

Thus, we have ΔNBA~ΔABC and ΔNAC~ΔABC. So, for ΔNBA and ΔABC, we have

\frac{BN}{BA} = \frac{BA}{BC}
\frac{BN}{20} = \frac{20}{25}
\overline{BN} = \frac{20(20)}{25} = 16

and applying the same process with AN, we have

\frac{AN}{BA} = \frac{AC}{BC}
\frac{AN}{20} = \frac{15}{25}
\overline{AN} = \frac{20(15)}{25} = 12

We can also use the same method to find the missing sides in ΔANC. But, we can immediately find the value of NC as shown.

\overline{NC} = \overline{BC} - \overline{BN}
\overline{NC} = 25 - 16 = 9

Since ΔANC is a right triangle and two given lengths, we can find the third side, AN, through Pythagorean theorem. 

\overline{AN} = \sqrt{15^{2} - 12^{2}} = 9

Thus, we have found all the missing sides. The picture attached also shows the missing sides' lengths in red. 

Answer: BC = 25, BN = 16, NC = 9, and AN = 12

6 0
3 years ago
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