All categories

2 years ago

How can i model 5/2 divided by 1/4

Mathematics

1 answer:

kotykmax [81]2 years ago

4 0

Yes multiply by opposite

You might be interested in

Compute $14A6_{12} - 5B9_{12}$. Give your answer as a base $12$ integer.

avanturin [10]

Answer:

you need to 12 minus 5b9 as base and don’t forget to mention the integer

4 0

3 years ago

13 copies of the small rectangle shown below have been used to make the larger rectangle.

Nikolay [14]

Answer:

4800

Step-by-step explanation:

length = 20mm X 3 = 60mm

width = 20mm X 4 = 80mm

area = length X width = 60 X 80 = 4800 m $m^{2}$

I hope it helps you!

8 0

2 years ago

Pls help this is an ixl question and it really is hard

valentina_108 [34]

Answer:

It would be the first one... 10:25

Step-by-step explanation:

10/4=2.5

2.5*10=25

2.5*4=10

7 0

3 years ago

If 123 and x are in proportion find the value of x

Marizza181 [45]

1:2=3:x

1/2=3/x

1×x=3×2

x=6

3 0

3 years ago

Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f

Korvikt [17]

If there is some scalar function $f(x,y)$ such that

$\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j$

then we want to find $f$ such that

$\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)$
$\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C$
$\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C$

So the vector field $\mathbf f(x,y)$ is conservative, which means the fundamental theorem applies; the line integral of $\mathbf f$ along any path $\mathcal C$ parameterized by some vector-valued function $\mathbf r(t)$ over $a\le t\le b$ is given by

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))$

In this case,

$\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23$

5 0

3 years ago