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likoan [24]
3 years ago
14

Lashonda, Carlos, and Jim have a total of 59$ in their wallets. Jim has 2 times what Lashonda has. Carlos has 5$ less than Lasho

nda. How much does each have?
Mathematics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

Lashonda has $16, Jim has $32, and Carlos has $11

Step-by-step explanation:

let's say the amount of money each person has is a variable: L, C, and J for Lashonda, Carlos, and Jim respectively.  

J=2L, and C+5=L, and L+C+J=59.

Let's only use Lashonda for this problem.

(2L)+(L-5)+(L)=59. This is equal to  

4L-5=59. 59+5=64.  

4L=64; 64/4=16, so Lashonda has $16    

If we follow the rules, we get:  

J=32, L=16, and C=11.

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Ok so remember
order of simplification
PEMDAS
parenthaseese
exponents
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addition or subtraction whichever comes first

ok so remmeber work from the left to right parenthasees first and work from inside to outer parenthasees

so first one

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second one
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so answe ris a=-2
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third questions

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ok
1. subtrac 4 from 2
2. a=-2, b=9
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