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likoan [24]
3 years ago
14

Lashonda, Carlos, and Jim have a total of 59$ in their wallets. Jim has 2 times what Lashonda has. Carlos has 5$ less than Lasho

nda. How much does each have?
Mathematics
1 answer:
Oliga [24]3 years ago
4 0

Answer:

Lashonda has $16, Jim has $32, and Carlos has $11

Step-by-step explanation:

let's say the amount of money each person has is a variable: L, C, and J for Lashonda, Carlos, and Jim respectively.  

J=2L, and C+5=L, and L+C+J=59.

Let's only use Lashonda for this problem.

(2L)+(L-5)+(L)=59. This is equal to  

4L-5=59. 59+5=64.  

4L=64; 64/4=16, so Lashonda has $16    

If we follow the rules, we get:  

J=32, L=16, and C=11.

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7 0
4 years ago
A red ribbon 11 meters long is 5 times as long as a blue ribbon. How long is the blue ribbon?​
aev [14]

Red ribbon

=Blue ribbon ×5

=11 m

<em>So</em><em>,</em><em> </em><em>changes</em><em> </em><em>the</em><em> </em><em><u>times</u></em><em><u> </u></em><em><u>symbol</u></em><em> </em><em>into</em><em> </em><em><u>divide</u></em>

11m ÷ 5

=2.2m

Check!

Red ribbon=Blue ribbon × 5

11m=Blue ribbon × 5

11m÷5=Blue ribbon

2.2m=Blue ribbon

Blue ribbon=2.2m

Answers

2.2m

5 0
3 years ago
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