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Andrei [34K]
4 years ago
12

The base ticket price for a football game is modeled by the function p(x) = 15x + 10, where x is the years since the team starte

d playing football. Not included in each base ticket price is a service charge modeled by the function c(x) = 5x + 2. To find the total cost of a ticket, a fan should use what operation on the polynomials?
Addition

Subtraction

Multiplication

It cannot be determined
Mathematics
2 answers:
lora16 [44]4 years ago
7 0

Answer:  First option is correct.

Step-by-step explanation:

Since we have given that

Price of base ticket for a football game is given by

p(x)=15x+10

Service charge modeled by the function is given by

c(x)=5x+2

We need to find the total cost of a ticket :

p(x) + c(x)

= 15x+10+5x+2

=20x+12

So, we have used Addition operation on the polynomials.

Hence, First option is correct.

Svetllana [295]4 years ago
6 0
The total cost of the ticket is the sum of the base ticket price, p(x) = 15x + 10, and the service charge, c(x) = 5x + 2. Therefore, from the word sum, the operation involved is Addition. This is the first among the choices given.
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Is it possible for a logarithm to equal a negative number and why?
Lesechka [4]

The only numbers you can plug into a logarithm are positive numbers not equal to 1. Negative numbers, and the number 0, aren’t acceptable arguments to plug into a logarithm, but why?

The reason has more to do with the base of the logarithm than with the argument of the logarithm. To understand why, we have to understand that logarithms are actually exponents. The base of a logarithm is also the base of a power function.

When you have a power function with base 0, the result of that power function is always going to be 0. In other words, there’s no exponent you can put on 0 that won’t give you back a value of 0. Or, put a different way, 0 raised to anything is always still 0. In the same way, 1 raised to anything is always still 1.

If you raise a negative number to a positive number that’s not an integer, but instead a fraction or a decimal, you might end up with a negative number underneath a square root. And as you know, unless we’re getting into imaginary numbers, we can’t deal with a negative number underneath a square root.

So 0, 1, and every negative number presents a potential problem as the base of a power function. And if those numbers can’t reliably be the base of a power function, then they also can’t reliably be the base of a logarithm.

For that reason, we only allow positive numbers other than 1 as the base of the logarithm. Then what we know is that, if the base of our power function is positive, it doesn’t matter what exponent we put on that base (it could be a positive number, a negative number, of 0), that power function is going to come out as a positive number.

So in summary, because the base can only be a positive number, that means the argument of the logarithm can only be a positive number. Which means that in order to protect our bases, we have to only allow positive arguments inside the logarithm.

Hope this helps!

6 0
3 years ago
20 for this question needing help
Radda [10]

Step-by-step explanation:

option C is the answer.

hope it helps

7 0
2 years ago
How do I solve for x?
Ket [755]

Answer:

x=17

Step-by-step explanation:

The Pythagorean theorem

a^2 + b^2 =c^2  where a and b are the legs  and c is the hypotenuse

8^2 + (x-2)^2 = x^2

64 + (x-2)(x-2) = x^2

FOIL

64 + x^2 -2x-2x+4 = x^2

Combine like terms

68+x^2 -4x  = x^2

Subtract x^2 from each side

68+x^2-x^2 -4x  = x^2-x^2

68 -4x = 0

Add 4x to each side

68-4x+4x= 4x

68 = 4x

Divide by 4

68/4 = 4x/4

17 = x

3 0
4 years ago
Read 2 more answers
Paco orders an ice cream for $1, but realizes his wallet is at home and he only has 3/20 of $1 with him. If his mom pays the rem
Svet_ta [14]

Answer: the answer is c) $0.85


Step-by-step explanation:

if he has 3/20 of a dollar that calculates to $0.15 and $1.00 minus $0.15 equals $0.85

3 0
4 years ago
3 out of 4 divided by 1 out of 16 fraction
baherus [9]

Answer:

12

Step-by-step explanation:

Given

\frac{3}4} ÷ \frac{1}{16}

Leave the first fraction, change division to multiplication and turn the second fraction upside down, that is

\frac{3}{4} × \frac{16}{1} ← cancel 4 and 16 by 4

= \frac{3}{1} × \frac{4}{1} = \frac{4(3)}{1(1)} = \frac{12}{1} = 12

5 0
4 years ago
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