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Free_Kalibri [48]
2 years ago
15

Find m A. 50° B. 55° C. 60° D. 65°

Mathematics
1 answer:
umka21 [38]2 years ago
6 0
I need more context to answer this question.
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Draw a rough sketch of a quadrilateral KLMN. State, (a) two pairs of opposite sides, (b) two pairs of opposite angles, (c) two p
kogti [31]

Answer:

Please find attached the drawing of quadrilateral KLMN created with MS Whiteboard using the Ink to Shape command

(a) Two pairs of opposite sides are \overline {KN}, \overline {LM} and \overline {KL}, \overline {NM}

(b) Two pairs of opposite angles are ∠LKN, ∠LMN, and ∠KLM and ∠KNM

(c) Two pairs of adjacent sides are \overline {KN}, \overline {NM} and \overline {KL}, \overline {LM}

(d) Two pairs of adjacent angles are ∠LKN, ∠KLM and ∠LMN, ∠KNM

Step-by-step explanation:

7 0
2 years ago
PLEASE HELP (100 POINTS)
omeli [17]

\\ \rm\Rrightarrow 2sin^2x=1-cosx

\\ \rm\Rrightarrow 2sin^2x=1-1+sin^2x

\\ \rm\Rrightarrow 2sin^2x-sin^2x=0

\\ \rm\Rrightarrow sin^2x=0

\\ \rm\Rrightarrow sinx=0

\\ \rm\Rrightarrow x\in n\pi

6 0
1 year ago
Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))
Marrrta [24]

Answer:

\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Step-by-step explanation:

\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine \frac{1}{c} + \frac{1}{h}

\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}

Combine the bottom, too.

=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}

Apply the fraction rule

=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}

Cancel

=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

Therefore, \frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}

5 0
2 years ago
Write an equation of the line that is perpendicular to 3x - 4y equals 9 + contains (-4, -5)
Inga [223]
  • Slope-Intercept Form: y = mx+b, with m = slope and b = y-intercept

So perpendicular lines have <u>slopes that are negative reciprocals</u> to each other, but firstly we need to find the slope of the original equation. The easiest method to find it is to convert this standard form into slope-intercept.

Firstly, subtract 3x on both sides of the equation: -4y=-3x+9

Next, divide both sides by -4 and your slope-intercept form of the original equation is y=\frac{3}{4}x-\frac{9}{4}

Now looking at this equation, we see that the slope is 3/4. Now since our new line is perpendicular, this means that <em>its slope is -4/3.</em>

Now that we have the slope, plug that into the m variable and plug in (-4,-5) into the x and y coordinates to solve for the b variable as such:

-5=-\frac{4}{3}*-4+b\\\\-5=5\frac{1}{3}+b\\\\-10\frac{1}{3}=b

<u>In short, your new equation is y = -4/3x - 10 1/3.</u>

3 0
3 years ago
Read 2 more answers
A test was given to a group of students. The grades and gender are summarized below
jasenka [17]

Answer:

<h3>★ <u>11/30</u> is the right answer. ★</h3>

Step-by-step explanation:

  • Number of male students who got 'A' in the test is 11
  • Number of female students who got 'A' in the test is 19
  • Total students who got 'A' in the test is 30
  • Probability that the male student got an 'A' is P(A | male) = (Number of male students who got 'A' in the test)/(Number of total students who got 'A' in the test) = <em><u>11/30</u></em>
4 0
2 years ago
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