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valina [46]
4 years ago
7

I need to write these description into the new function but I keep getting the wrong thing -.-

Mathematics
1 answer:
12345 [234]4 years ago
5 0
Since you're studying this stuff, you know that
.. translation right by k units: f(x) ⇒ f(x-k)
.. translation up by k units: f(x) ⇒ f(x) +k
.. horizontal stretch by a factor of k: f(x) ⇒ f(x/k) . . . . same as compressed by 1/k
.. vertical stretch by a factor of k: f(x) ⇒ k*f(x)
.. reflection across the x-axis: f(x) ⇒ -f(x)
.. reflection across the y-axis: f(x) ⇒ f(-x)
The sequence in which these are done is important.

1. f(x) = (1/2)^x
.. translated 4 units right: f(x) = (1/2)^(x -4)
.. reflected across the x-axis: f(x) = -(1/2)^(x -4)
.. vertically stretched by a factor of 1.5: f(x = -1.5(1/2)^(x -4)

2. f(x) = ln(x)
.. translated 3 units left: f(x) = ln(x +3)
.. horizontally compressed by a factor of 1/4: f(x) = ln(x/4 +3)
.. translated down 0.5 units: f(x) = -0.5 +ln(x/4 +3)

3. f(x) = e^x
.. horizontally stretched by a factor of 3: f(x) = e^(x/3)
.. reflected across the y-axis: f(x) = e^(-x/3)
.. translated 1 unit right: f(x) = e^(-(x -1)/3)
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Then, we must do trial and error for each of the options until we find one that fits perfectly. Luckily, the first option was right!

Hope this helps

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<h3>Answer: Choice D.  5x-5 \ge 0</h3>

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The +1 at the end doesn't affect the domain.

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Select the correct answer. What is the area of the triangle in the diagram? A. B. C. D. Reset Next Previous5 Next Using Coordina
Komok [63]

The area of the triangle can be calculated using the distance formula if the coordinates are given.

<h3>What is the triangle?</h3>

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

We have a triangle with coordinates on the coordinate plane.

It is required to find the area of the triangle using the coordinate points.

Here the coordinates are not given, so we are assuming the coordinates are (x1, y1), (x2, y2), (0,0)

From the distance formula:

The distance(b) between (0, 0) and (x1, y1):

\rm b = \sqrt{(x_1-0)^2+(y_1-0)^2} \Rightarrow \sqrt{x_1^2+y_1^2}

The distance between (0, 0) and (x2, y2):

\rm h = \sqrt{(x_2-0)^2+(y_2-0)^2} \Rightarrow \sqrt{x_2^2+y_2^2}

So the area of the triangle:

A = bh/2

\rm A = \dfrac{1}{2}\times  \sqrt{x_1^2+y_1^2} \times  \sqrt{x_2^2+y_2^2}

\rm A = \dfrac{1}{2} \sqrt{(x_1^2+y_1^2) (x_2^2+y_2^2)}

Thus, the area of the triangle can be calculated using the distance formula if the coordinates are given.

Learn more about the triangle here:

brainly.com/question/25813512

#SPJ1

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