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Levart [38]
3 years ago
14

The probability that a person cannot read is 0.85 what is the probability that 2 people selected at random will be unable to rea

d
Mathematics
1 answer:
Alina [70]3 years ago
3 0

Answer: 0.7225

Step-by-step explanation:

Since the probability that a person cannot read is 0.85. The probability that 2 people selected at random will be unable to read will be gotten by multiplying the value of the probability given twice. This will be

= P(not read) × P(not read)

= 0.85 × 0.85

= 0.7225

Therefore, the probability that 2 people selected at random will be unable to read is 0.7225

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32% of a number is 64 what is the number
Serjik [45]

Answer:

If you take 32 percent of a number and get 64, then what is that number? In other words, you know that 32 percent of a number is 64 and you want to know what that initial number is. Therefore, the answer to "64 is 32 percent of what number?" is 200, and you can also derive that 32 percent of 200 equals 64.

Step-by-step explanation:

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3 years ago
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Please help with this question!
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The correct answer choice is A. I think!
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Eduardo is building a sandbox that has an area of 84 square feet. What are the possible whole number measurements for the length
kicyunya [14]
Try this option:
1. note, that the number 84 is divided by numbers: 1;2;3;4;6;7;12;14;21;28;42 and 84. It means, that measurements of the length may be: 1;2;3;4;6;7;12;14;21;28;42;84 and for the width: 84;42;28;21;14;12;7;6;4;3;2;1.
2. according the numbers calculated in item 1, the possible number measurements for the length and width of the sandbox are (length; width):
1;84
2;42
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3 years ago
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Plot function f on the graph f(x) = |1/2x - 2|​
Assoli18 [71]

Answer:

  • See attached

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = |1/2x - 2|​

The function is plotted and it is below.

8 0
3 years ago
You are given the polar curve r=1+cos(θ).
MrRissso [65]
For the answer to the question above,
 <span>r = 1 + cos θ 

x = r cos θ 
x = ( 1 + cos θ) cos θ 
x = cos θ + cos^2 θ 
dx/dθ = -sin θ + 2 cos θ (-sin θ) 
dx/dθ = -sin θ - 2 cos θ sin θ 

y = r sin θ 
y = (1 + cos θ) sin θ 
y = sin θ + cos θ sin θ 
dy/dθ = cos θ - sin^2 θ + cos^2 θ 

dy/dx = (dy/dθ) / (dx/dθ) 
dy/dx = (cos θ - sin^2 θ + cos^2 θ)/ (-sin θ - 2 cos θ sin θ) 

For horizontal tangent line, dy/dθ = 0 

cos θ - sin^2 θ + cos^2 θ = 0 
cos θ - (1-cos^2 θ) + cos^2 θ = 0 
cos θ -1 + 2 cos^2 θ = 0 
2 cos^2 θ + cos θ -1 = 0 
Let y = cos θ 

2y^2+y-1=0 
2y^2+2y-y-1=0 
2y(y+1)-1(y+1)=0 
(y+1)(2y-1)=0 
y=-1 
y=1/2 

cos θ =-1 
θ = π 
cos θ =1/2 
θ = π/3 , 5π/3 

θ = π/3 , π, 5π/3 
when θ = π/3, r = 3/2 
when θ = π, r = 0 
when θ = 5π/3 , r = 3/2 
(3/2, π/3) and (3/2, 5π/3) give horizontal tangent lines 
</span>---------------------------------------------------------------------------------
For horizontal tangent line, dx/dθ = 0 

<span>-sin θ - 2 cos θ sin θ = 0 </span>
<span>-sin θ (1+ 2 cos θ ) = 0 </span>
<span>sin θ = 0 </span>
<span>θ = 0, π </span>

<span>(1+ 2 cos θ ) =0 </span>
<span>cos θ =-1/2 </span>
<span>θ = 2π/3 </span>
<span>θ = 4π/3 </span>

<span>θ = 0, 2π/3 ,π, 4π/3 </span>
<span>when θ = 0, r=2 </span>
<span>when θ = 2π/3, r=1/2 </span>
<span>when θ = π, r=0 </span>
<span>when θ = 4π/3 , r=1/2 </span>

<span>(2,0) , (1/2, 2π/3) , (0, π), (1/2, 4π/3) </span>
<span>At (2,0) there is a vertical tangent line</span>
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