Matthew is making a sequence in which -3 is added to each successive term. The 6th term in his sequence is -1. What is the 1st t
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Answer:
Step-by-step explanation:
Given:
Time spent on Monday (M) =
Time spent on Tuesday (T) =
Now, the total combined time spent on study is equal to the sum of the times spent on Monday and Tuesday.
So, we need to add both the times to get the combined time spent on studying.
The combined study time is given as:
Total time spent = Time spent on Monday + Time spent on Tuesday
Divide 281 by 36. The quotient is the whole number part, the remainder is the numerator part and the denominator remains the same.
So, on dividing, we get 7 as quotient and 29 as remainder. So, converting to mixed fractions, we get:
Therefore, the the combined time he spent studying is
See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0
<h3>How to graph the hyperbola?</h3>The equation of the hyperbola is given as:
12x^2 - 3y^2 - 108 = 0
Start by calculating the transverse axis
So, we have:
<u>Transverse axis</u>
The vertices of the given hyperbola are (0, 0)
This means that
(h, k) = 0
Where
a = 3 and b = 6
The transverse axis is calculated as:
y = ±b/a(x - h) + k
So, we have:
y = ±6/3(x - 0) + 0
Evaluate the difference and sum
y = ±6/3x
Evaluate the quotient
y = ±2x
This means that the transverse axes are y = 2x and y =-2x
<u>The vertices</u>
In the above section, we have:
The vertices of the given hyperbola are (0, 0)
This means that
(h, k) = 0
<u>The co-vertices</u>
In the above section, we have:
The vertices of the given hyperbola are (0, 0)
This means that
(h, k) = 0
And
a = 3 and b = 6
The co-vertices are
(h - a, k) and (h + a, k)
So, we have:
(0 - 3, 0) and (0 + 3, 0)
Evaluate
(-3,0) and (3, 0)
See attachment for the graph of the hyperbola
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