Answer:
The checkbook balance is $178 .7.
Step-by-step explanation:
As given
Sherry had an ending balance $ 125.36, outstanding deposits of $153.53, and outstanding checks of $100.19.
Thus
Checkbook balance = Ending balance + Outstanding deposits - Outstanding checks
Putting the values in the above
Checkbook balance = $ 125.36 + $153.53 - $100.19
= $ 278.89 - $100.19
= $ 178.7
Therefore the checkbook balance is $178 .7.
Answer:
First option: 
Step-by-step explanation:
The missing graph is attached.
The equation of the line in Slope-Intercept form is:

Where "m" is the slope and "b" is the y-intercept.
We can observe that:
1. Both lines have the same y-intercept:

2. The lines are solid, then the symbol of the inequality must be
or
.
3. Since both shaded regions are below the solid lines, the symbol is:

Based on this and looking at the options given, we can conclude that the graph represents the following system of inequalities:

Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
<span>Slope of JK=((-1)-2)/(4-(-3)=-3/7
Slope of KL=((-5)-(-1)/(2-4=2
Slope of LM=((-2)-(-5))/(-5-2)=-3/7
Slope of MJ=(2-(-2))/((-3)-(-5))= 2
JK is parallel to LM and KL is parallel to MJ. Therefore JKLM is a parallelogram.</span>