Answer:
d = ![\frac{5x}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B2%7D)
Step-by-step explanation:
Height of the person = 6 feet
Height of the lamppost = 10 feet
Let the distance between the man and end of shadow be = y
By using the concept of similar triangles:
![\frac{y}{6}=\frac{x}{10-6} }](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B6%7D%3D%5Cfrac%7Bx%7D%7B10-6%7D%20%7D)
=> ![\frac{y}{6}=\frac{x}{4} }](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B6%7D%3D%5Cfrac%7Bx%7D%7B4%7D%20%7D)
So, y = ![\frac{3x}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3x%7D%7B2%7D)
Now distance d will be = x + y
= ![x+\frac{3x}{2}](https://tex.z-dn.net/?f=x%2B%5Cfrac%7B3x%7D%7B2%7D)
d = ![\frac{5x}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B2%7D)
<h3>☘︎Answer :- </h3>
![\sf\longmapsto \: \frac{371}{36}](https://tex.z-dn.net/?f=%20%5Csf%5Clongmapsto%20%5C%3A%20%20%5Cfrac%7B371%7D%7B36%7D%20)
<h3>☘︎ Solution :- </h3>
- Given : Three sides are 11/3 cm , 15/4 cm and 26/9 cm
- To find : perimeter of the triangle
Perimeter of a triangle = Sum of the length of the three sides
perimeter of the given triangle = 11/3 + 15/4 + 26/9
- Make the denominator same by taking the LCM of the denominators .
( LCM of 3 , 4 and 9 is 36 )
![\sf\longmapsto \: \frac{132 \: + \: 135 \: + \: 104}{36} \: \: \:](https://tex.z-dn.net/?f=%5Csf%5Clongmapsto%20%5C%3A%20%20%5Cfrac%7B132%20%5C%3A%20%20%2B%20%20%5C%3A%20135%20%20%5C%3A%20%2B%20%5C%3A%20%20104%7D%7B36%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
![\sf\longmapsto \: \frac{371}{36} \: cm \:](https://tex.z-dn.net/?f=%5Csf%5Clongmapsto%20%5C%3A%20%20%5Cfrac%7B371%7D%7B36%7D%20%5C%3A%20%20cm%20%5C%3A%20)
♧ Therefore, the perimeter of a triangle is 371/36 cm
Answer:
65
Step-by-step explanation:
Your welcome! 3.66 is your right answer!
Answer:
Both are similar by SAS similarity.
This SAS similarity is equivalent to the congruence.
Step-by-step explanation:
Step 1:
To prove that ACB and HIG as similar triangles.
We have to look upon the corresponding sides.
SAS= Side angle sides , there the angle must be in between two sides.
ACB =
HIG
Lets work on the corresponding sides.
IG/AC = IH/AC
= ![\frac{12}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B20%7D)
Reducing each to lowest form, we divide numerator and denominator by 3 for the 1st fraction and by 4 for the 2nd fraction.
We have
= ![\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D)
Both sides are equal.
So its proved that both are similar with SAS similarity theorem.