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3 years ago

Find the indicated side of the triangle !!!

Mathematics

2 answers:

babymother [125]3 years ago

7 0

Answer:

b = 6

Step-by-step explanation:

The above questions is trigonometry where hypothenus = 12; opposite = b; and adjacent = a. Applying SOHCAHTOA principle, the appropriate is

Sine = opposite/hypothesis, since we are to find the value of b. Thus,

Sine 30 = b/12

0.5 =b/12

By cross multiplying,

b = 0.5 × 12

b = 6

maks197457 [2]3 years ago

5 0

Answer:

The correct answer is b = 6 √3 units

Step-by-step explanation:

Let's recall that we can use the following ratio for the sides of a 90 - 60 - 30 triangle:

1 : √3 : 2, where 2 is the hypotenuse.

Upon saying that, we have that in our triangle:

Hypotenuse = 12 units

a = 6 units

b = 6 √3 units

The correct answer is b = 6 √3 units

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Step-by-step explanation:

Given that the triangles are similar then the ratios of corresponding sides are equal, that is

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Step-by-step explanation:

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Step-by-step explanation:

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6. Assume that a component passes a test is 0.85 and that components perform independently. What is the probability that the thi

Tanzania [10]

Answer:

3.90% probability that the third failure will occur on the tenth component tested

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not fail. Components perform independently. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that a component passes a test is 0.85

So they fail with probability of $p = 1 - 0.85 = 0.15$

What is the probability that the third failure will occur on the tenth component tested

First 9 components: Two failures, that is, P(X = 2) when n = 9.

10th component: Failure with probability 0.15.

$P = 0.15P(X = 2)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{9,2}.(0.15)^{2}.(0.85)^{7} = 0.2597$

$P = 0.15P(X = 2) = 0.15*0.2597 = 0.0390$

3.90% probability that the third failure will occur on the tenth component tested

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3 years ago