<span>Were going to try and solve each system using the elimination method: x - 3y = -7 (Equation 1) 2x = 6y - 14 (Equation 2)
From Equation 1: x - 3y = -7 Add 3y to each side of the equation: x - 3y + 3y = -7 + 3y Therefore: x = -7 + 3y Substitute x = -7 + 3y into Equation 2. Equation 2: 2x = 6y - 14 2(-7 + 3y) = 6y - 14 -14 + 6y = 6y - 14 Add 14 to each side of the equation. We remain with: 6y = 6y y = 0 <span>OK, now we continue :)
</span></span><span>Substitute y = 0 into Equation 1: x - 3y = -7 x - 3(0) = -7 x - 0 = -7 Add 0 to each side of the equation: Therefore: x = -7
X - 3y = -7 this is formula 1 2x = 6y-14 this is formula 2 from formula 1, we can change it to x = -7 + 3y. this is formula 3 now we know x in terms of y sub it into formula 2 2(-7+3y) = 6y - 14 -14 + 6y = 6y -14 y=0 sub y = 0 into 3 x = -7 + 3x0 x = -7 so x is -7 and y is 0
