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adell [148]
3 years ago
5

50a3 + 10a2

Mathematics
2 answers:
Lady_Fox [76]3 years ago
3 0
50a^3+10a^2\\\\50a^3=10\cdot5\cdot a^2\cdot a=10a^2\cdot5a\\\\50a^3+10a^2=10a^2\cdot5a+10a^2\cdot1=\huge\boxed{10a^2(5a+1)}\to\boxed{A}
laila [671]3 years ago
3 0
50a^3+10a^2=10a^2(5a+1)\Rightarrow A
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Convert to scientific notation ​
Ainat [17]

Answer:

5.7* 10 to the power of 4

4 0
3 years ago
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Can you resolve this?<br><br> A= Area<br> P= Perimeter<br> AT= Total Area<br><br> plis help D:
Paraphin [41]

Answer:

in steps

Step-by-step explanation:

upper square:  P = 20x² + 8

<u>side: P/4 = 5x² + 2</u>

<u>A = side² = (5x² + 2)² = 25x⁴ + 20x² + 4</u>

Middle equilateral Triangle: A = x² + 4x + 4       base = 2x + 4

A = base x height / 2

(x + 2)² = 2 (x + 2) x height /2

<u>height = x + 2</u>

<u>perimeter = 2 (x + 2) x 3 = 6x + 12</u>

Lower trapezoid: A₁ = 2x² + 24x + 40 = 2 (x² + 12x + 20) = 2 (x + 2) (x + 10)

A₁ = (x + 10)² = 2 (x + 2) (x + 10)

x + 10 = 2x + 4

x = 6

<u>A₂ = (2x + 4) (x + 10) / 2 = (16 x 16) / 2 = 128</u>

A₁ = (6 + 10)² = 256

<u>AT = 256 + 128 = 384</u>

6 0
3 years ago
Diagonals of parallelograms<br><br> Solve for x
Lunna [17]

Diagonals bisect each other

\\ \bull\tt\longmapsto 2x+10=3x

\\ \bull\tt\longmapsto 3x-2x=10

\\ \bull\tt\longmapsto x=10

Option B

3 0
3 years ago
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Fittoniya [83]

Answer:

none of the above

Step-by-step explanation:

All of the answer choices agree that the magnitude of the components is 150/√2 ≈ 106.1. The units of these components should be "mph", the same as the units of the magnitude of the given vector.

We only know the angle with respect to horizontal. We don't know whether that angle is measured with respect to the positive x-axis or the negative x-axis. Both of those are horizontal, and there is nothing in the problem statement that restricts the airplane to be traveling in one direction or the other.

Possible answers are ...

<106.1 mph, -106.1 mph> . . . . . . "horizontal" is +x direction

<-106.1 mph, -106.1 mph> . . . . . "horizontal" is -x direction

(The units are not degrees (°).)

8 0
3 years ago
there are balls between 20 and 40, when Max counts them by 5's there is one left, when he counts it by three he finds 2 balls le
Aneli [31]

Answer:

So because the range is between 20 and 40, it can be noticed through counting.

5, 10, 15, 20, 25, 30, 35, 40

3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39

The number of balls in the box, just from the information by 5, is either ending in 1 (for example 21, 31) or 6 (26, 36)

From counting by 3 with that information, it would mean the number is most likely 26 balls, since there would be one left when Max reaches 25 counting by 5, and two left when he reaches 24 counting by 3.

3 0
2 years ago
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