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adell [148]
3 years ago
5

50a3 + 10a2

Mathematics
2 answers:
Lady_Fox [76]3 years ago
3 0
50a^3+10a^2\\\\50a^3=10\cdot5\cdot a^2\cdot a=10a^2\cdot5a\\\\50a^3+10a^2=10a^2\cdot5a+10a^2\cdot1=\huge\boxed{10a^2(5a+1)}\to\boxed{A}
laila [671]3 years ago
3 0
50a^3+10a^2=10a^2(5a+1)\Rightarrow A
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The table below represents a function. Which of the following equations could be its function rule?
worty [1.4K]

Answer:

y=2x-2 is the required equation.

Therefore, the second option is true.

Step-by-step explanation:

We know that the slope-intercept form of the line equation of a linear function is given by

y=mx+b

where m is the slope and b is the y-intercept

Taking two points (0, -2) and (1, 0) from the table to determine the slope using the formula

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(0,\:-2\right),\:\left(x_2,\:y_2\right)=\left(1,\:0\right)

m=\frac{0-\left(-2\right)}{1-0}

m=2

substituting the point (0, -2) and the slope m=2 in the slope-intercept form to determine the y-intercept i.e. 'b'.

y=mx+b

-2 = 2(0)+b

-2=0+b

b=-2

Now, substituting the values of m=2 and b=-2 in the slope-intercept form to determine the equation of a linear function

y=mx+b

y=2x+(-2)

y=2x-2

Thus, y=2x-2 is the required equation.

Therefore, the second option is true.

3 0
3 years ago
A rectangle has a perimeter of 58. The width is 7 less than the length. Find the length
Marianna [84]

Answer:

Length = 18 Width = 11

Step-by-step explanation:

Perimeter = 2(length) + 2(width)

So let's label the unknown length as x. Width would then be (x-7). Then plug it into the perimeter equation.

2(x) + 2(x-7) = 58

Then use PEMDAS which will give us

2x+2x-14 = 58

Combine like terms

4x -14 = 58

Add 14 to both sides

4x = 72

To get x by itself you have to divide both sides by 4.

x = 18

So length is 18 and width is (18-7) which is 11.

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2 years ago
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Answer:

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Step-by-step explanation:

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