The quadratic formula is ![\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%5B2%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
and in the equation ax^2+bx+c=0
so now all you have to do is substitute the numbers into the quadratic formula
This equation uses two properties of logarithms:


So you could take the ln from left and right hand side in the equation, and get:
(2-x)ln 3 = x ln 5
then
2 ln 3 - x ln 3 - x ln 5 = 0 =>
x(ln 3 + ln 5) = 2 ln 3
so x = 2 ln 3 / (ln3 + ln5)
Now using the 1st property you can say 2 ln 3 is ln 3² = ln9
and using the 2nd property you can say ln3 + ln5 = ln15
so x= ln9 / ln15
Answer:

Step-by-step explanation:



Answer: 225
Step-by-step explanation:
Volume of the pyramid is calculated as 1/3 bh, where b is base and h is height
Given height as 39cm and a base of 10√3cm = 10 x √3, where √3= 1.73; base = 10 x 1.73 = 17.3
Slot the values into the formula:
Volume = 1/3 × 17.3 x 39
= 1/3 × 674.7 = 674.7/3
Volume = 224.9 approximately 225.
I hope this helps.