Find the smallest positive integer that has a remainder of 2 when divided by 4 and remainder of 3 when divided
1 answer:
Answer:
18
Step-by-step explanation:
Hello
The number is more by three than a multiple of of 5 (i.e 5x +3) and more than 2 than a multiple of 4 (ie 4y+2(
Now 5x+3=4y+2
ie 5x +1 =4y
we need to give the lowest pair of values to x and y such that the last equality is satisfied.
By trial, x = 3 and y = 4
thus the number is 5x+3 =5(3)+3 =18=4y+2 =4(4)+2=18
I hope it has helped you.
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