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3 years ago

What value should be added to the expression to create a perfect square?

Mathematics

1 answer:

raketka [301]3 years ago

5 0

25 would be your final answer.

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Given that the measurement is in centimeters, find the area of the circle to the nearest tenth. (Use 3.14 for π) the radius is 3

Fofino [41]

Answer:

Area of the circle = $28.26cm^2$

Step-by-step explanation:

Radius of the circle= 3 cm

Area of the circle= $\pi *r^2$

As,

$\pi =\frac{22}{7}=3.14$

Putting the values in the formula:

Area of the circle= $3.14*3*3$

$=3.14*9\\\\=28.26cm^2$

The area of the circle is $28.26cm^2$

3 0

4 years ago

Solve the following system using either linear combination or substitution. Round any answers to the hundredths place. Show all

12345 [234]

So if y=-5x-23 then we can plug that value in for y in x-10y=6, so it becomes

x-10(-5x-23)=6

x+50x+230=6

51x=-224

x=-4.39

plug this x value into the equation y=-5x-23

y=-5(-4.39)-23

y=21.95-23

y=-1.05

3 0

3 years ago

Eathan ran 11 miles in 2 hours. what is the unit rate of miles to hours

spayn [35]

Answer:

5.5:1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find the value of x

romanna [79]

they are 2 similar triangles, one is smaller than the other. they are in the ratio of 2:1,

hence 7x =56÷2

7x=28

x=4

4 0

3 years ago

Consider this right triangle. 21 29 20 Enter the ratio equivalent to s

AleksAgata [21]

Answer:

Part 1) $sin(B)=\frac{21}{29}$

Part 2) $csc(A)=\frac{29}{20}$

Part 3) $cot(A)=\frac{21}{20}$

Step-by-step explanation:

The complete question is

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

$cot(A)=\frac{21}{20}$

4 0

3 years ago