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2 years ago

Plz help I have 10 mins left!

Mathematics

2 answers:

DedPeter [7]2 years ago

5 0

The answer is C. Here’s how

Mumz [18]2 years ago

4 0

Answer:

Step-by-step explanation:

For future questions like this find an ordered pair like (2,6) and substitute them in to each formula

example it said g=3t so g would be the 6 and t would be the 2

6= 3(2)

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What is the hight of a Building 1 Angle 71o Distance 20 meters

vlabodo [156]

The height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.

<h3>What is trigonometry?</h3>

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We have:

Angle = 71 degree

Distance between A and B = 20 meters

Let's suppose the height of the building is x meters.

From the right angle triangle applying the tan ratio:

tan71 = x/20

x = 58.08 meter

Thus, the height of a building is 58.08 meters if the angle is 71 degree and the distance between A and B is 20 meters.

Learn more about trigonometry here:

brainly.com/question/26719838

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6 0

1 year ago

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

2 years ago

A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to

Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

$P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916$