Answer:Both Technicians A and B are correct.
Explanation:Teflon is a florinated polymer it is polytetrafluroethylene (PTFE). It is widely used in different fields and the making of materials for both home and industrial use. Teflon rings does requires special tools for proper installation which is called TEFLON RING INSTALLER.
Warming the a Teflon ring in water or oil at 130-140°F for about 5 minutes will help to soften the material for easier installation. cover wear ring grooves with plastic tape.
Answer:
#include <iostream>
#include <ctime>
#include <cstdlib>
using namespace std;
int menu();
int doubleIt(int);
int getPower(int,int);
int reverse(int);
int power(int);
int sum(int);
int twoDigit(int);
int threeDigit(int);
bool prime(int);
int main()
{int n;
srand(time(0));
n=rand()%90+10;
do
{
cout<<"The number is: "<<n<<endl<<endl;
switch(menu())
{case 1: n=doubleIt(n);
break;
case 2: n=reverse(n);
break;
case 3: n=power(n);
break;
case 4: n=sum(n);
break;
case 5: n=twoDigit(n);
break;
case 6: n=threeDigit(n);
break;
case 7: return 0;
}
if(prime(n))
cout<<n<<" is prime\n";
else
cout<<n<<" is not prime\n\n";
if(n<10)
n+=10;
}while(true);
}
int doubleIt(int n)
{return n*2;
}
int power(int n)
{int p;
cout<<"Enter 2, 3 or 4th power: ";
cin>>p;
while(p<2||p>4)
{cout<<"invalid entry\n";
cout<<"Enter 2, 3 or 4th power: ";
cin>>p;
}
return getPower(n,p);
}
int reverse(int n)
{int newnum=0;
while(n>0)
{newnum=newnum*10+n%10;
n=n/10;
}
return newnum;
}
int sum(int n)
{int sum=0;
while(n>0)
{sum=sum+n%10;
n=n/10;
}
return sum;
}
int twoDigit(int n)
{int d1,d2;
if(n<100)
{d1=n%10;
d2=n/10;
return getPower(d1,d2);
}
return n;
}
int threeDigit(int n)
{int d1,n2;
if(n>99)
{d1=n%10;
if(d1<=4)
{n2=n/10;
return getPower(n2,d1);
}
}
return n;
}
bool prime(int n)
{int i;
for(i=2;i<n-1;i++)
if(n%i==0)
return false;
return true;
}
int getPower(int x,int y)
{int ans,i;
if(y==0)
return 1;
else
{ans=x;
for(i=2;i<=y;i++)
ans=ans*x;
return ans;
}
}
int menu()
{int choice=8;
while(choice<1||choice>7)
{cout<<"1. double the number\n";
cout<<"2. reverse the digit of the number\n";
cout<<"3. raise the number to the power of 2,3, or 4\n";
cout<<"4. sum thee digits of the number.\n";
cout<<"5. if the number is a two digit number\n then raise the first digit to the power of the second digit\n";
cout<<"6. If the number is a three digit number\n";
cout<<" and the last digit is less than or equal to 4\n then raise the first two digits to the power of the last digit.\n";
cout<<"7. exit\n";
cin>>choice;
}
return choice;
}
Answer:
A
Explanation:
The same formats are being applied.
Which best describes the main idea of this paragraph? (2 points)
This bird population is very diverse.